2. Most ARM processors support both Big Endian and Little Endian. ARM processor is Little Endian by default. Endian big little First byte (lowest address) most significant least significant Memory Address 0x8000 0x8001 0x8002 0x8003 0x8004 Middle bytes *** Memory Data OXEE 0x8C 0x90 OxA7 OxFF By default setting, the word stored at address 0x8000 is: Last byte (highest address) least significant most significant
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- Most Intel CPUs use the __________, in which each memory address is represented by two integers.physcal addresses are 4s ng 4 Ame dat in a cetain compe, te addresses can be translaled without y TLB entries At most how many ditina vid the address translation peh has 12 vld The Translation Look aside Bulfer (TLB)i sine is kB and the word size iby The memory is word addresible. The pe virtual addresses are 64 bea long d th sine is miss?For 8086 microprocessor, the stack segment may have a memory block of a maximum of 32K bytes O 64K bytes O 16K bytes O Option 4 O
- What is the total capacity in hexadecimal representation for any segment base address within the 8086 microprocessor's real address mode RAM?Options: FEFFh BHAFh EEEEh FFFFhSignal is used to indicate whether the operation is belongs to the memory ot s periphevals 8 The. order address presented on the multiplexed address data :bus. signal helps to capture the lower can be used to store the input/aitput address and string main pulation. Signal is active, it indicates 10 when the to the other processors not to ask the Cpu to Leave the sys tem bus.Q/ Design the basic interface for 8486 Microprocessor. Hint : Address and Data multiplex or not ? 2 6:23
- The memory unit of a computer has 128K words of 32 bits each. The computer has an instruction format with four fields: an operation code field, a mode field to specify one of 5 addressing modes, a register address field to specify one of 6 processor registers, and a memory address. Specify the number of bits in each field of the instruction if it occupies one memory word. bits bits bits bits Op-code Addressing Mode Register AddressMemory AddressThe interrupt vector for INT 06 is located at the physical address ___________. 00000 00003 00006 00012 00018 00024Maximum memory that can be addressed by Intel 8086 microprocessor is 1Mbytes because: Select one: a. It has segment registers b. It has 20 wires in its address bus c. It is 16 bits processor d. It has 16 wires in its address bus e. It has 20 bits IP register
- Of the total 1.2M of Real Mode memory what is the first 640K of memory is used for: a-The interrupt vector table b-Upper memory (EMS) c- Conventional memory d-Expanded memory e-Extended memory (XMS)O True O False Question 11 The decoding of 80x86 instructions are simpler than instructions in ARM processors. True O False D Question 12 All instructions of LEGV8 are 32 bits long. O True O False Question 13 In 80x86 assembly language, before calling a function or procedure, you must write a PUSH state address on the Stack. O True O FalseIt will be very difficult to correct mistake in unique design or adding new options in already design of control unit. * True O False control unit controls the flow of data between the processor and ROM and peripherals. True O False DATA BUS It is a unidirectional bus while ADDRESS BUS is It is a bidirectional bus. * O True O False