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- 3. For protection, the barrel barrier is placed in front of a bridge pier. The relationship between the force and deflection of the barrier is as given in the plot. For a car weighing 4000 lb and travelling at 50 mph as it first impacts the barrier, find the penetration of the car into the barrier. Note: One interpretation of Up = fF.dr is that work is the area under the force-deflection curve. F (lb) F=90(10)³x¹/2 -x (ft)Blocks mị and m2 are connected by a rope as shown in the figure. There is friction between mi and the wall, where the coefficient of static friction is ls. There is no friction between m2 and the ramp. An unknown force P is applied to mį so that mị is about to slip down the wall and m2 is about to move down the ramp. If the magnitude of the normal force on m2 is n2, find m2, the magnitude of P, the magnitude of the friction force on m1, and the magnitude of the tension force in the rope. The knowns are ls, n2, m1, g, and 0. P = ? Hs rope wall no friction m2 = ? rampFill in the blanks: Determine the tension in the string and acceleration of the block A and B weighing 1200 N and 400 N connected by a string as shown in figure Assume pulleys are weightless and frictionless. A 400N 1200N (a)
- no friction Will the ladder slip? A ladder of length l = 4m rests against a wall at 0 = 60°. Assume that there is no friction between the ladder and A ladder the vertical wall but there is friction between the ground and the ladder with u = 0.5. A person weighing 700 N starts to climb up the ladder. 1. Can the person make it to the top safely (without the ladder slipping)? If not, then find the distance d along the ladder that the person can climb safely. Ignore the weight of the ladder in comparison to the weight of the person. 2. Does the "no slip" distance d depend on ? If yes, then find the angle 0 which makes it safe for the person to reach the top. W frictionQ2/ In the proell governor shown in figure below, the arm ABC is formed in one piece. Each ball has a mass of 1.8 kg and the effect of friction is equivalent to a force of 9N at the sleeve. AB = 150 mm , BC = 50 mm, and BD = 150 mm. Find the magnitude of the central load on the sleeve, if the governor is to rise to its mean position as shown in the diagram when the speed is 120 r.p.m, the portion BC of the lower arm then being vertical. The gravitational effect of the balls must be taken into account. 25 mm B 225 mm 25 mmTwo bodies is connected in point C, are supported by rigid underlay at an angle α. F is the force acting on right body. We are considering the weight of bodies G and the friction between the bodies and the underlay. Length of bodies l=2000mm. G1= 160 N, G2= 180 N, α = 30° Find: 1.) Find the magnitude of the force so that it slips on the underlay 2.) Draw the dependence of the force F as a function of the coefficient of friction f (in the range 0-0.5)
- Problem A block with a mass of 15 kg sits on the smooth incline shown below where the angle is e = 37°. The block is attached to the wall via a spring with a spring constant of k = 246 N/m. The coordinate system for this problem is oriented as shown in the diagram. Based on this information, answer the following: a) Determine the distance the spring must stretch to offset the weight component of the block in the x-direction (this is where your x-direction datum will be located). b) Create a free body diagram and use the force balance in the x-direction to develop the second-order ordinary differential equation governing the motion of the block (your force balance should be based upon the datum found in part a). c) Find the natural frequency (wn), the period of vibration (T), and the frequency (f). d) For an undamped, freely vibrating system the solution to the second-order ordinary differential equation developed in part b has the form x(t) = Asin(wnt) + Bcos(wnt). If at time t = 0 s…A 70 lb-bag of rice is being pulled by a person by applying a force F at an angle 0. The force required to drag the bag is F(0) = (70p)/(µsine + cose) where u = 0.35 is the coefficient of friction. Determine the maximum F by creating a vector for the angle with elements ranging from 5° to 35° and spacing of 0.01 and use the built-in function max. The maximum F isThe figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure. Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (F₁) and (b) the normal force from the shoulder joint (F acting on the humerus bone that holds the arm in this equilibrium position. S (a) Number (b) Number i Fa 0.075 m O 12⁰ 0.250 m Units Units W arm 0.510 m 5 kg WA
- Two box hang from the ends of a string suspended from a frictionless pulley. The mass on the left is chosen to create a tension of 4 N in the string. The box on the right has a weight of 2 N. What will be the acceleration of the box on the right? Assume the acceleration of gravity is 9.8 m/s?. 4 N 2 N6. 2) The uniform slender 14-kg bar of length /= 3.2 m rests on smooth surfaces but starts to slide in a way that the contact point at A moves to the left while the contact point at B moves downwards. If at this instant the angle 0 = 60°, and the normal force at point B is 3.3 N, determine the normal force at point A at this instant. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper Sl unit. Take g = 9.81 m/s?. B A1. An Atwood machine (shown below) consists of a pulley with two weights W₁ = 100 N and W₂ = = 200 N attached at the end of the string. T is the tension in the string and a is the acceleration of the system. If the tension and the acceleration satisfy the set of equations: T-W₁ = = 10a W₂-T = 20a Solve for the tension 7 and the acceleration a. It's okay if you do not understand the physics right now. Solve as a systems of linear equation problem. Solve for T and a: T= a = b WI 2 W2 N m/s²