theory of computation(automata theory) 1- Show that bellow Language is not RegularUsing pumping Lemma1-L= {w|we (aub) * [w/9=2/w/b}1

To show that the language (L={w∣w∈(a∪b)∗,∣w∣a=2∣w∣b}) is not regular using the pumping lemma, we…

Answered: 1- Show that bellow Language is not…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Use the Pumping Lemma to show the following language L is NOT regular. L= {w E (a, b, c}* ; where w has equal number of a's, b's, and c's}
(4p) Let us have the following regular grammarG. Apply the method of regular equations on conversion ofGinto regular expressionVsuch thatL(G)=h(V). \[ \begin{array}{l} G=\{\{A, B, C\},\{0,1\}, P, A) \\ P=\{A \rightarrow 0|1 C| E \\ B \rightarrow 0 B|1 C| 0 \\ C \rightarrow 1 C|1| 0 B\} \end{array} \]
5. Prove that the following language is not regular: L8 = {a"bmamb" | n 2 0, m > 1}.
8. Build a DPDA that accepts the language L = {(ab)" (aab)b² n ≥0
a)Prove that the following language is not regular. L = {w.w': w∈ {a, b}*| w' is obtained by replacing all a’s by aa’s and all b’s by bb’s}.
Create a PDA that accepts the language L = {w ∈ {a.b}* : na(v) ≥ nb(v), where v is any prefix of w}
prove the following languages below are not regular using fooling sets.
3. Give a DPDA that accepts the language {(ab) (ba)' : i > 0}
Prove that the following language is regular.L = {x | x ∈ {0, 1}∗, x does not contain five consecutive 0's or five consecutive 1's}Hint: You may take advantage of some closure properties.
Given: Language L1 = {aa, b, bc}Determine: 3th Power of L1 = L1^3Hint: The Power of L is the set of all subsets of L
Build a DPDA that accepts the language L ={(ab)" (aab)b²n |n≥0
Show that the following language is not context free. DO NOT use pumping lemma. {a*b"c"b" | n> k> 0}

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1- Show that bellow Language is not Regular Using pumping Lemma 1- L= {w|we (aub) * [w/9=2/w/b} 1