If we are interested in studying known regions of the genome associated with a particular phenotype, we should refer to a: Question 16 options: Physical map Linkage map Genetic linkage Genetic markers Quantitative trait locus (QTL) map
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Question 16 options:
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Physical map
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Linkage map
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Genetic linkage
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Genetic markers
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Quantitative trait locus (QTL) map
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- Consider the parental cross rY x RR, where r is the trait/disease allele, and R is the wild-type allele. The mode of inheritance is sex-linked recessive. Compute the ratios (Wild-type/non-disease phenotype):(Disease phenotype) for the F1 and F2 generations. Check the syllabus to see what formats are allowable for submission (e.g., pdf, docx, etc). Note: if you use a text editor like Notepad, you must use Courier New font. Also, you must show all work, akin to the work shown in the pdf lecture. Hint: In the F1 generation, individuals can only mate with the opposite gender.SEATWORK Symbols (for pea plant traits): • T: Tall t: short Analyze the following problems. Determine the possible genotypes, genotypic ratio, phenotypes, and phenotypic ratio from the genetic cross. Show your solution through a Punnett square. Use the symbols provided. • R: Round seeds r: wrinkled seeds • Y: Yellow seeds y: green seeds • P: Purple flower p: white flower 1) Cross a homozygous dominant tall and homozygous round seed pea plant with a heterozygous tall and heterozygous round seed pea plant. 2) Cross a pea plant that is heterozygous for purple flowers and homozygous dominant for yellow seeds with a pea plant that is heterozygous for purple flowers and homozygous recessive for green seeds. 3) Cross a pea plant that is short and has green seeds with a pea plant that is heterozygous tall and has heterozygous yellow seeds.Pedigree Analysis Is a Basic Method in Human Genetics Pedigree analysis permits all of the following except: a. an orderly presentation of family information b. the determination of whether a trait is genetic c. the determination of whether a trait is dominant or recessive d. an understanding of which gene is involved in a heritable disorder e. the determination of whether a trait is sex-linked or autosomal
- Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the following questions. a. Is the proband male or female? b. Is the grandfather of the proband affected? c. How many siblings does the proband have, and where is he or she in the birth order?A proband female with an unidentified disease seeks the advice of a genetic counselor before starting a family. Based on the following data, the counselor constructs a pedigree encompassing three generations: (1) The maternal grandfather of the proband has the disease. (2) The mother of the proband is unaffected and is the youngest of five children, the three oldest being male. (3) The proband has an affected older sister, but the youngest siblings are unaffected twins (boy and girl). (4) All the individuals who have the disease have been revealed. Duplicate the counselors featYou are interested in finding the quantitative trait locus associated with a phenotype. You should explore a: Cytogenic map Linkage map Physical map Google maps Dora's map
- Notation: D = disease allele at gene d = wild-type allele at gene Let’s provide some information about each MOI. AD: Each of the F1 parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother’s genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female 301 Total 1157 DF p-value In Table 2, provide expected proportions for two different MOIs: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected)…You may insert a hand-drawn diagram of your map, but the rest of the assignment must be fully typed. The data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable.Answer in less than 30 words:Why are mathematical /statistical tools needed in the understanding of the transmission of traits in the field of Genetics?
- A RFLP is discovered that is linked to the gene for Duchenne’s muscular dystrophy (DMD). DMD is an X-linked, recessive trait. The RFLP is 2 map units from the gene for DMD. Consider the following pedigree and Southern blot using a probe that hybridizes to the RFLP. Which band/s is/are associated with DMD? What is the genotype for individuals 3 and 4? (Remember, this is an X linked disease, so use X’s and Y’s to denote). Individual 9 married a man who does NOT have muscular dystrophy, and she is pregnant. DMD is an X-linked trait. What is the probability for their child to have DMD? An amniocentesis is performed and it is determined that 9’s child in utero has only a 10 kb band that hybridizes to the same probe used above. What can you say about the child now?A genetic disorder is caused by a LOF mutation (Bm) and epigenetic imprinting of gene B. Through pedigree analysis of many families, researchers have observed the following results: Female carrier B+Bm x B+B+ --> B+Bm and Mother's genotype Father's genotype Children's genotype Children's phenotype Cross 1: B+Bm B+B+ B+Bm , B+B+ some affected, some unaffected Cross 2: B+B+ B+Bm B+Bm , B+B+ always unaffected Based on these results, gene B is imprinted on the: a. maternal b. paternalBelow is a pedigree showing transmission of a disease; affected individuals are indicated by solid circles or boxes. Represented below the pedigree are two nylon membranes; DNA samples from each individual in the pedigree were spotted in identical fashion on each membrane. Each individual's DNA appears directly below his or her position in the pedigree. Each membrane was hybridized with allele specific oligonucleotides that detect the two alternative alleles of a single SNP locus (ASO 1 and ASO 2). Positive hybridization is represented as a filled circle and lack of hybridization is represented as an open circle. I 11 III IV V ASO 1 ASO 2 To 1 2 3 4 5 6 a. What is the mode of transmission of this disease? 12 b. Which SNP allele (ASO1 or ASO2) is originally linked to the disease gene? c. Draw a diagram of the event that gave rise to the genotype of individual IV-5. d. Individual V-1 is an unborn fetus. If the SNP locus is 10 CM from the disease locus, what is the likelihood that he will…