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Extraction of acetone from trichloroethane 1000 kg/h of a 45 wt% solution of acetone (A) in water (W) is to be extracted with pure 1,1,2-trichloroethane (TCE) in a continuous counter-current system. Using the equilibrium data below: a) Construct the equilibrium curve for the liquid-liquid region in the ternary system. b) Identify the solute, carrier and solvent. Briefly explain your choice. c) Determine the minimum flow rate of solvent to achieve phase split.

Extraction of acetone from trichloroethane 1000 kg/h of a 45 wt% solution of acetone (A) in water (W) is to be extracted with pure 1,1,2-trichloroethane (TCE) in a continuous counter-current system. Using the equilibrium data below: a) Construct the equilibrium curve for the liquid-liquid region in the ternary system. b) Identify the solute, carrier and solvent. Briefly explain your choice. c) Determine the minimum flow rate of solvent to achieve phase split.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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could someone show clearer working and reasoning behind solotion 

Tutorial 7 - Question Q1 Extraction of acetone from trichloroethane 1000 kg/h of a 45 wt% solution of acetone (A) in water (W) is to be extracted with pure 1,1,2-trichloroethane (TCE) in a continuous counter-current system. Using the equilibrium data below: a) Construct the equilibrium curve for the liquid-liquid region in the ternary system. b) Identify the solute, carrier and solvent. Briefly explain your choice. c) Determine the minimum flow rate of solvent to achieve phase split. Concentrations in phase 1 (wt%) Concentrations in phase 2 (wt%) Xw Xw 13 35 4 3 2 1.5 1 ХА 60 50 40 30 20 10 XTCE 27 46 57 68 78.5 89 W Tutorial 7 - Question Q1 ХА 55 50 40 30 20 10 Extraction of acetone from trichloroethane W 35 Extraction of acetone from trichloroethane 12 13. A 30- x + 43 57 68 79 89.5 Tutorial 7 - Question Q1a Solution A X A V 4 K X 60 A 55 XTCE 10 X 7 3 2 1 0.5 A University of Strathclyde Engineering Tie line data Raffinate Extract X₁ (wt%) X₁ (wt%) 44 56 29 40 12 18 TCE TCE University of Strathclyde ☆ University Strathclyde Engineering
Transcribed Image Text:Tutorial 7 - Question Q1 Extraction of acetone from trichloroethane 1000 kg/h of a 45 wt% solution of acetone (A) in water (W) is to be extracted with pure 1,1,2-trichloroethane (TCE) in a continuous counter-current system. Using the equilibrium data below: a) Construct the equilibrium curve for the liquid-liquid region in the ternary system. b) Identify the solute, carrier and solvent. Briefly explain your choice. c) Determine the minimum flow rate of solvent to achieve phase split. Concentrations in phase 1 (wt%) Concentrations in phase 2 (wt%) Xw Xw 13 35 4 3 2 1.5 1 ХА 60 50 40 30 20 10 XTCE 27 46 57 68 78.5 89 W Tutorial 7 - Question Q1 ХА 55 50 40 30 20 10 Extraction of acetone from trichloroethane W 35 Extraction of acetone from trichloroethane 12 13. A 30- x + 43 57 68 79 89.5 Tutorial 7 - Question Q1a Solution A X A V 4 K X 60 A 55 XTCE 10 X 7 3 2 1 0.5 A University of Strathclyde Engineering Tie line data Raffinate Extract X₁ (wt%) X₁ (wt%) 44 56 29 40 12 18 TCE TCE University of Strathclyde ☆ University Strathclyde Engineering
Tutorial 7 - Question Q1a Solution Extraction of acetone from trichloroethane W Carrier W Tutorial 7 - Question Q1b Solution Extraction of acetone from trichloroethane d 4 W Solute A Feed F XAF 0.45 . . Extraction of acetone from trichloroethane The minimum concentration of solvent to achieve phase split is given by the green dot (M): XAM = 0.44 XW.M= 0.52 XTCEM = 0.04 A (.) . A • Solute: Acetone Tutorial 7 - Question Q1c Solution TCE . Solvent: Trichloroethane This is the compound we want to extract > Phase split at low concentrations • Carrier: Water ➤ Originally carries the solute Solvent TCE The slope of the tie lines increases. from the carrier to the solvent Overall balance: M=F+S Component balance: XAM M=XAFF+XAS S Carathclyde University of University of Strathclyde Solvent S ✓✓XAS=0 TCE S=F* (XAF-XAM)/XAM S = 1000 (0.45-0.44) / 0.44 S = 23 kg/h University of Strathclyde
Transcribed Image Text:Tutorial 7 - Question Q1a Solution Extraction of acetone from trichloroethane W Carrier W Tutorial 7 - Question Q1b Solution Extraction of acetone from trichloroethane d 4 W Solute A Feed F XAF 0.45 . . Extraction of acetone from trichloroethane The minimum concentration of solvent to achieve phase split is given by the green dot (M): XAM = 0.44 XW.M= 0.52 XTCEM = 0.04 A (.) . A • Solute: Acetone Tutorial 7 - Question Q1c Solution TCE . Solvent: Trichloroethane This is the compound we want to extract > Phase split at low concentrations • Carrier: Water ➤ Originally carries the solute Solvent TCE The slope of the tie lines increases. from the carrier to the solvent Overall balance: M=F+S Component balance: XAM M=XAFF+XAS S Carathclyde University of University of Strathclyde Solvent S ✓✓XAS=0 TCE S=F* (XAF-XAM)/XAM S = 1000 (0.45-0.44) / 0.44 S = 23 kg/h University of Strathclyde
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could you touch further on the last slide, where does the mixing point come from and also tie lines ?

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