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Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is MY Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations X Y X- Mx Y - MY Squared Deviations (X - MX)² (Y - MY)² Products (X-MX) (Y - MY) 2 2 3 3 4 4 1 6 10 10 The sum of squares for x is SSX = The sum of squares for y is SSy = . The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because Suppose you are given the following five pairs of scores: X Y 2 2 3 3 4 4 1 6 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. 10 9 8 7 5 + (?)

Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is MY Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations X Y X- Mx Y - MY Squared Deviations (X - MX)² (Y - MY)² Products (X-MX) (Y - MY) 2 2 3 3 4 4 1 6 10 10 The sum of squares for x is SSX = The sum of squares for y is SSy = . The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because Suppose you are given the following five pairs of scores: X Y 2 2 3 3 4 4 1 6 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. 10 9 8 7 5 + (?)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 15PPS
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Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is MY Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations X Y X- Mx Y - MY Squared Deviations (X - MX)² (Y - MY)² Products (X-MX) (Y - MY) 2 2 3 3 4 4 1 6 10 10 The sum of squares for x is SSX = The sum of squares for y is SSy = . The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because
Transcribed Image Text:Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is MY Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations X Y X- Mx Y - MY Squared Deviations (X - MX)² (Y - MY)² Products (X-MX) (Y - MY) 2 2 3 3 4 4 1 6 10 10 The sum of squares for x is SSX = The sum of squares for y is SSy = . The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because
Suppose you are given the following five pairs of scores: X Y 2 2 3 3 4 4 1 6 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. 10 9 8 7 5 + (?)
Transcribed Image Text:Suppose you are given the following five pairs of scores: X Y 2 2 3 3 4 4 1 6 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. 10 9 8 7 5 + (?)
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