An isolated water molecule is modeled as two point charges ±0.700e separated by 0.0980 nm. Its rotational inertia is 2.93 × 10⁻⁴⁷ kg·m² about the axis shown in the figure below. The molecule is in a uniform electric field of magnitude 838 N/C. If the molecule is initially at rest at θ = 90.0°, what is its angular speed when it reaches θ = 0, assuming no other forces or torques?

rad/s

Transcribed Image Text:An isolated water molecule is modeled as two point charges ±0.700e separated by 0.0980 nm. Its rotational inertia is 2.93 × 10-47 kg·m² about the axis shown in the figure below. The molecule is in a uniform electric field of magnitude 838 N/C. If the molecule is initially at rest at 0 = 90.0°, what is its angular speed when it reaches 0 = 0, assuming no other forces or torques? +9 rad/s Axis of rotation Ꮎ

Question

An isolated water molecule is modeled as two point charges ±0.700e separated by 0.0980 nm. Its rotational inertia is 2.93 × 10⁻⁴⁷ kg·m² about the axis shown in the figure below. The molecule is in a uniform electric field of magnitude 838 N/C. If the molecule is initially at rest at θ = 90.0°, what is its angular speed when it reaches θ = 0, assuming no other forces or torques?

rad/s

An isolated water molecule is modeled as two point charges ±0.700e separated by
0.0980 nm. Its rotational inertia is 2.93 × 10-47 kg·m² about the axis shown in the figure
below. The molecule is in a uniform electric field of magnitude 838 N/C. If the molecule is
initially at rest at 0 = 90.0°, what is its angular speed when it reaches 0 = 0, assuming no
other forces or torques?
+9
rad/s
Axis of
rotation
Ꮎ

Accepted Answer

Answered: Image /qna-images/answer/fbc2776a-c20d-401d-a8ec-3c44f2963531.jpg