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-0.64.1 (None] 0,20 Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer PCC)-.20 The Probability of choosing a incorrect answer P(() = 80. X Denates the number of correct. answers x=0,1,2 0.20 0.04 0.80 0.80 getting none right by guessing 0.36 One 0.20 980 P(x=27=0,20x0.20 P(x)=0,20x0,80 P(x=1=0,20x0.80 →0.16 + (x=0)=0.80 x 0.80 +0.64 The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting 0,4, and both right x 0 1 2 PG=A) 0.64 0.32/0.04 0.04 Both

-0.64.1 (None] 0,20 Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer PCC)-.20 The Probability of choosing a incorrect answer P(() = 80. X Denates the number of correct. answers x=0,1,2 0.20 0.04 0.80 0.80 getting none right by guessing 0.36 One 0.20 980 P(x=27=0,20x0.20 P(x)=0,20x0,80 P(x=1=0,20x0.80 →0.16 + (x=0)=0.80 x 0.80 +0.64 The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting 0,4, and both right x 0 1 2 PG=A) 0.64 0.32/0.04 0.04 Both

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Find the expected value of the number of questions you'd get right by guessing. What are the variance and standard deviation? (The pictures attached show work from the other question in order to anwer the question. Thank you)

-0.64.1 (None Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer P(C) = -20 The Probability of choosing a incorrect answer P(() = .80 0,20 0.80 getting none right by guessing 0.36 one X Denates the number of corred p(x=27=0.20 0.20 answers x=0,1,2 0.04 0.80 0.20 P(x)=0.20*0.80 P(x=1=0,20x0.80 → 0.16 аво The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting and both right 0.04 151 (Both + (x=0)=0.80 x 0.80 +0.64 X 0 1 2 PGx=x) 0.64 0.32/0.04
Transcribed Image Text:-0.64.1 (None Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer P(C) = -20 The Probability of choosing a incorrect answer P(() = .80 0,20 0.80 getting none right by guessing 0.36 one X Denates the number of corred p(x=27=0.20 0.20 answers x=0,1,2 0.04 0.80 0.20 P(x)=0.20*0.80 P(x=1=0,20x0.80 → 0.16 аво The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting and both right 0.04 151 (Both + (x=0)=0.80 x 0.80 +0.64 X 0 1 2 PGx=x) 0.64 0.32/0.04
You're taking a multiple-choice exam and you don't know the answers to two of the questions. Each question has five choices, so the probability of getting a question right by guessing is .20. Draw a tree diagram showing the probabilities of getting none, one, or both questions right by guessing. P(X=x) = ()P/-P)n-x X is random variable denote of questions quessed right n=2&P=0₁2 non quessed Right P(x=0) = (2) x(0.2))x(1-0.2) (2-0) 02-0) (0.8)2 = 2 1x0.64 = non quesses right 0.64 =64 One guessed right P(x-1)=(2)x(0.2) ¹x (1-0.2) (2-1) = 7(2-1) × (0.2) ¹x (0.8)' x = 2x0.2x0.8 0.32 One guessed right is 0.32 both guessed right P(x-2)=(2)x(0.2)x(1-0.2) (² = 2(2-2) × (0.2)² x (0.8) O =1*0.04=0.04 Both guessed right is 0.04
Transcribed Image Text:You're taking a multiple-choice exam and you don't know the answers to two of the questions. Each question has five choices, so the probability of getting a question right by guessing is .20. Draw a tree diagram showing the probabilities of getting none, one, or both questions right by guessing. P(X=x) = ()P/-P)n-x X is random variable denote of questions quessed right n=2&P=0₁2 non quessed Right P(x=0) = (2) x(0.2))x(1-0.2) (2-0) 02-0) (0.8)2 = 2 1x0.64 = non quesses right 0.64 =64 One guessed right P(x-1)=(2)x(0.2) ¹x (1-0.2) (2-1) = 7(2-1) × (0.2) ¹x (0.8)' x = 2x0.2x0.8 0.32 One guessed right is 0.32 both guessed right P(x-2)=(2)x(0.2)x(1-0.2) (² = 2(2-2) × (0.2)² x (0.8) O =1*0.04=0.04 Both guessed right is 0.04
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