Quiz 6 Attempt 2

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American Military University *

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302

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Statistics

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Jan 9, 2024

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docx

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17

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Question 1 1 / 1 point A researcher is testing reaction times between the dominant and non-dominant hand. They randomly start with each hand for 20 subjects and their reaction times in milliseconds are recorded. Test to see if the reaction time is faster for the dominant hand using a 5% level of significance. The hypotheses are: H 0 : μ D = 0 H 1 : μ D > 0 t-Test: Paired Two Sample for Means Non- Dominant Dominant Mean 63.33 56.28 Variance 218.96431 58 128.75221 05 Observations 20 20 Pearson Correlation 0.9067 Hypothesized Mean Difference 0 df 19
t Stat 4.7951 P(T<=t) one-tail 0.0001 t Critical one-tail 1.7291 P(T<=t) two-tail 0.0001 t Critical two-tail 2.0930 What is the correct test statistic? 2.0930 1.7291 0.0001 4.7951 0.9067 Hide question 1 feedback The Test stat is 4.7951. This is given to you in the output. No calculations are needed. The Test stat is 4.7951. This is given to you in the output. No calculations are needed. Question 2 1 / 1 point A manager wants to see if it worth going back for a MBA degree. They randomly sample 18 managers' salaries before and after undertaking a MBA degree and record their salaries in thousands of dollars. Assume Salaries are normally distributed. Test the claim that the MBA degree, on average, increases a manager's salary. Use a 10% level of significance. t-Test: Paired Two Sample for Means
New Salary Old Salary Mean 61.878 56.999 Variance 177.5551 115.8012 Observations 18 18 Pearson Correlation 0.7464 Hypothesized Mean Difference 0 df 17 t Stat 2.9870 P(T<=t) one-tail 0.0024 t Critical one-tail 1.3334 P(T<=t) two-tail 0.0048 t Critical two-tail 1.7396 The hypotheses for this problem are:
H 0 : μ D = 0 H 1 : μ D > 0 What is the correct test statistic? 1.7396 1.3334 2.9870 0.7464 Hide question 2 feedback The Test stat = 2.9870. This is given to you in the output. No calculations are needed. Question 3 1 / 1 point In clinical trials of a newly developed cold medicine, it was found that 45 out of 200 individuals that took the new medicine (Group 1) experienced an upset stomach as a side effect and 33 out of 150 individuals that took a placebo (Group 2) experienced an upset stomach. Test to see if the new drug produced a significantly higher proportion of individuals experiencing upset stomach. Use a 0.01 level of significance. Select the correct alternative hypothesis and decision. H 1 : p 1 p 2 ; Do not reject the null hypothesis. H 1 : p 1 p 2 ; Reject the null hypothesis. H 1 : p 1 > p 2 ; Do not reject the null hypothesis. H 1 : p 1 > p 2 ; Reject the null hypothesis. H 1 : p 1 < p 2 ; Do not reject the null hypothesis. H 1 : p 1 < p 2 ; Reject the null hypothesis. Hide question 3 feedback
This is an upper tailed test because keyword is higher. z = .225−.22.222857 .777143 (1/200+1/150) z = 0.1112 Use NORM.S.DIST(0.1112,TRUE) to find the for the lower tailed test. 0.544284, to get the upper tailed test you take 1 - 0.544284, this is the p-value you want to use for the conclusion. Question 4 1 / 1 point The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her listeners are at least 22 years old and wants to know what age group she should gear her advertisements to for the games. She takes a random sample of 46 listeners from age 22-39 and 57 listeners who are 40 and older and asks them if they are likely to tune in to football games. The "yes" responses are recorded below. Age 22-39 (Group 1) Age 40+ (Group 2) Responded "Yes" to Football 32 47 Sample Size n 46 57 At the 0.05 level of significance, we are attempting to investigate if there is a significant difference in the proportion of listeners based on age. Enter the p-value - round to 4 decimal places. p-value = ___ 0.1239 ___ Hide question 4 feedback This is a two tailed test because you want to find significant difference.
z = .695652−.824561.76699 .23301 (1/46+1/57) z = -1.5385 Use NORM.S.DIST(-1.5385,TRUE) to find the for the lower tailed test. This value is smaller of the two, thus you will multiply it by 2 for a two tailed test 0.061962*2, this is the p-value you want to use for the conclusion. Question 5 1 / 1 point A math teacher tells her students that eating a healthy breakfast on a test day will help their brain function and perform well on their test. During finals week, she randomly samples 46 students and asks them at the door what they ate for breakfast. She categorizes 26 students into Group 1 as those who ate a healthy breakfast that morning and 20 students into Group 2 as those who did not. After grading the final, she finds that 50% of the students in Group 1 earned an 80% or higher on the test, and 40% of the students in Group 2 earned an 80% or higher. Can it be concluded that eating a healthy breakfast improves test scores? Use a 0.05 level of significance. Hypotheses: H 0 : p 1 = p 2 H 1 : p 1 > p 2 In this scenario, what is the test statistic? (Round to 4 decimal places) z = ___ 0.6750 ___ Hide question 5 feedback z = .50−.40.456522 .543478 (1/26+1/20)
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