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Zn(s) O Cu(s) the cathode in the cell is: O Cu ¹2 OPt (aq) Zn(s) + Cu+2 Zn +2 + Cu(s) (aq) → Zn+2 (aq) (aq)

Zn(s) O Cu(s) the cathode in the cell is: O Cu ¹2 OPt (aq) Zn(s) + Cu+2 Zn +2 + Cu(s) (aq) → Zn+2 (aq) (aq)

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter20: Electrochemistry
Section: Chapter Questions
Problem 60A
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Given the cell reaction, Zn(s) + Cut2 Cu(s) Cu +2 the cathode in the cell is: O Pt (aq) Zn(s) (aq) Zn(aq) → Zn¹2 + Cu(s) +2 (aq)
Transcribed Image Text:Given the cell reaction, Zn(s) + Cut2 Cu(s) Cu +2 the cathode in the cell is: O Pt (aq) Zn(s) (aq) Zn(aq) → Zn¹2 + Cu(s) +2 (aq)
The standard (half cell) reduction potentials of two reactions are given below. Li+ (aq) + e F2(g) + 2e¯ (aq) From this information, one may conclude that Li(s): Li(s) 2F is an excellent reducing agent is an excellent oxidizing agent is very difficult to oxidize will not react with F2(g) is very electronegative Eº = - 3.04 V E° +2.87 V
Transcribed Image Text:The standard (half cell) reduction potentials of two reactions are given below. Li+ (aq) + e F2(g) + 2e¯ (aq) From this information, one may conclude that Li(s): Li(s) 2F is an excellent reducing agent is an excellent oxidizing agent is very difficult to oxidize will not react with F2(g) is very electronegative Eº = - 3.04 V E° +2.87 V
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