You throw a metal block of mass 0.19 kg into the air, and it leaves your hand at time t= 0 at location <0, 2, 0> m with velocity <3.5, 4.5, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t= 0.05 s, t= 0.10 s, and t= 0.15 s. (Express your answers in vector form.)

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Chapter1: Units, Trigonometry. And Vectors
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Use the approximation that v→avg=p→f/m
for each time step.
You throw a metal block of mass 0.19 kg
into the air, and it leaves your hand at time
t= 0 at location <0, 2, 0> m with velocity
<3.5, 4.5, 0> m/s. At this low velocity air
resistance is negligible. Using the iterative
method shown in Section 2.4 with a time
step of 0.05 s, calculate step by step the
position and velocity of the block at t= 0.05
s, t= 0.10 s, and t= 0.15 s. (Express your
answers in vector form.)
Transcribed Image Text:Use the approximation that v→avg=p→f/m for each time step. You throw a metal block of mass 0.19 kg into the air, and it leaves your hand at time t= 0 at location <0, 2, 0> m with velocity <3.5, 4.5, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t= 0.05 s, t= 0.10 s, and t= 0.15 s. (Express your answers in vector form.)
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