You have two charges, one of size -4e, and one of size 1e. They are separated by a distance of 27 pm. Calculate the electric force between the two. Report your answer in microNewtons (N). Be sure to include sign in your answer, where positive means a repulsive force and negative means attractive. Remember, e = Your Answer: Answer 1.6 x 10-¹9 Cand 1pm = 10-¹²m
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- Electric force and coulomb balance1. By considering this assembly as being infinite plane plates uniformly loaded with the same load in absolute values, but of opposite signs; obtain a relation giving the electric field (Etot) between the plates as a function of the potential difference (delta V) between them and the distance (d) which separates the plates.2. Write the (simple) expression of the electric force on the movable plate having a charge Qmobile immersed in the electric field generated by the fixed plate (Efixe), see image on the left.3. From the notions of uniformly charged infinite flat plates, determine a relation giving the value of the charge of the movable plate (Qmobile) from the electric field (Emobile) that it generates.4. Substitute the relation obtained in #3 into the electric force relation from #2 and use the electric field relation from #1 to obtain an equation of electric force as a function of potential difference (delta V), knowing that Emovable = EFixed.5.…Electric force and coulomb balance1. By considering this assembly as being infinite plane plates uniformly loaded with the same load in absolute values, but of opposite signs; obtain a relation giving the electric field (Etot) between the plates as a function of the potential difference (delta V) between them and the distance (d) which separates the plates.2. Write the (simple) expression of the electric force on the movable plate having a charge Qmobile immersed in the electric field generated by the fixed plate (Efixe), see image on the left.3. From the notions of uniformly charged infinite flat plates, determine a relation giving the value of the charge of the movable plate (Qmobile) from the electric field (Emobile) that it generates.4. Substitute the relation obtained in #3 into the electric force relation from #2 and use the electric field relation from #1 to obtain an equation of electric force as a function of potential difference (delta V), knowing that Emovable = EFixed.5.…Final answers should be in two decimal places only. Include proper substitution and cancellation of units. An electron is placed in a uniform electric field of (given E) directed north created by two horizontal parallel plates that are (given distance) apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other? Given: Electri field (nN/C): 30 Distance (fm): 133
- This is a challenging problem. Solve it on paper, writing out each step carefully. When doing calculations, do not round intermediate values. Note: If you have approached the problem in a principled way, do not abandon your approach if your numerical answer is not accepted; check your calculations! Four protons (each with mass 1.7 x 10.27 kg and charge 1.6 x 10-19 C) are initially held at the corners of a square that is 5.1 x 10 mon a side. They are then released from rest. What is the speed of each proton when the protons are very far apart? (You may assume that the final speed of each proton is small compared to the speed of light.) Ufinal= m/sAnswer All.Compute for the work done, in millijoules, in moving a 9-nC charge radially away from the center from a distance of 3 m to a distance of 7 m against the electric field inside a solid insulating sphere of radius 11 m and total charge 7 mC.Ans: -8.5199Determine the total potential energy, in microjoules, stored in a parallelepiped of dimensions are 9 m by 6 m by 8 m if the electric field inside is given as E = 17 ar + 19 aθ + 15 aϕ V/m. Use the permittivity of free space as 8.854 × 10-12 F/m.Ans: 1.6734If the electric field in the region is given as E = -cos(θ) sin( 4 Φ) aθ + b cos( 4 Φ) aφ V/m. Determine the potential at point A(4 m, 0.46 rad, 2.07 m), in volts, if the potential at point B(4 m, 1.00 rad, 0.10 m) is 60 volts. The value of b is also the coefficient of Φ.58.4552 Compute for the potential difference, in volts, in moving a charge from A(3, 2, -2) m to B(7, -6, 6) m against the electric field due to a disk charge of radius 9 m on the plane x = 0. The disk has a…Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to λ this line of charge is given by E= 2kef= -, where is a unit vector directed radially outward Σπερμ from the infinitely long wire of charge. Hint #3 a. Letting the voltage be zero at some reference distance (V(ro) = 0), calculate the voltage due to this infinite line of charge at some distance r from the line of charge. Give your answer in terms of given quantities (A,ro,r) and physical constants (ke or Eo). Use underscore ("_") for subscripts and spell out Greek letters. Hint for V(r) calculation 3 V(r) = b. There is a reason we are not setting V(r → ∞o) = 0 as we normally do (in fact, in general, whenever you have an infinite charge distribution, this "universal reference" does not work; you need a localized charge distribution for this reference to work). Which of the following best describes what happens to potential as roo? (That is, what is V(ro), with our current…
- This one is tougher! A sphere of radius r has charge q. (a) What is the infinitesimal increase in clectric potential energy dU if an infinitesimal amount of charge dq is brought to infinity to the surface of the sphere? (b) An uncharged sphere can acquire a total charge Q by the transfer of charge dq over and over and over. Use your answer to part a to find an cxpression for the potential energy of a uniformly-charged sphere of radius R with total charge Q. Answer: U = 3_1 Q² 5 4tc0 R' (c) Your answer to part b is the amount of energy nceded to assemble a charged sphere. It is often called the self-energy of the sphere. What is the self-energy of a proton, assuming it to be a charged sphere with a diamcter of 1.0 x 10 15 m?part 1 of 2 Consider the field due to a uniformly charged disk of radius R. and charge Q. Along the symmetry axis at distance z from the cen- ter, the field has been written in following forms. where Eexact = Eo E₁ Eo part 2 of 2 2 R² + z² (1-7) (Q/A) 280 Eo = To compare the accuracy of different ap- proximations it is convenient to work with the normalized difference to be specified below. The nth order smallness is charac- terized by e" and € = with being the R smallness parameter. In general the nth or- der term takes the form Ce", where C is some finite constant (e.g 0.1 < C < 10). Eexact - E1| For the normalized difference Eo identify the correct choice among the follow- ing |E1 - Eo For the normalized difference Eo identify the correct choice among the follow- ing 1. 2. €³ 3. €2 4. € 1. € 2. €³ 3. €² 4. €4Imagine that two parallel plates are charged to achieve a voltage difference Vo between the plates. They have area A and spacing d. The plates are then electrically isolated so that no charge can be added or taken away. A good conductor of thickness d/2 is placed in between the two plates, as shown. Given that the charge on the plates cannot change, what is the electric field in the regions between the plates, but above and below the conductor? (If you are stuck, Gauss’s Law may help.)
- ... Path of trajectory AV w An electron is fired at a speed v¡ = 3.4 x 106 m/s and at an angle 0; = 30.5° between two parallel conducting plates as shown in the figure. If s = 1.5 mm and the voltage difference between the plates is AV = 98 V, determine how close, w, the electron will get to the %3D %3D bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.Determine the x-component of the electric field, in volts per meter, at (8.18, 7.47, 9.8) due to a very long uniform line charge of density 14 nC/m at x = -7.76 meters, z = -8.58 meters. All coordinates are measured in meters. Express your answers accurate to four decimal places.A conductor that carries a net charge Q has a hollow, empty cavity in its interior. Does the polential vary from point to point within the material of the conductor? What about within the caivity? How does the potential inside the cavity compare to the potential within the material of the conductor? For the toolbar, press ALT+F10 (PC) or AL FN+F10 (Mac). BIUS Paragraph vAV I S.. Arial 14px OWORDS POWERED BY TINY