You have been given two carbon fibre composite materials made using Intermediate Modulus carbon fibres and a toughened epoxy matrix; the first is a unidirectional material containing 36±2% by weight of resin and the second reinforced with a 200gm-2 balanced 2 x2 twill weave fabric. The cured ply thickness of the UD material is 0.14mm and that of the fabric 0.2mm. The fibre strength (o,) = 5,500MPa, fibre modulus (E₁) = 290GPa and density (p₁) = 1.8gcm-³. The matrix has a strength (m) = 50MPa, modulus (Em) = 4.5GPa and density (Pm) = 1.3gcm-3. The materials are to be used to design and manufacture a steering track rod for a prototype sports car. The track rod is to be fitted with spherical bearings either end. It will be of circular cross-section with an outer diameter of 10mm and length of 450mm. Maximum tensile load is predicted to be 11kN and that in compression 2kN. Assuming the compressive loading upon the laminate to be negligible, design a laminate able to provide a reserve factor of 2.0 (As a hint; treat the tube as a flat plate then apply the reserve load)

Elements Of Electromagnetics
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why W of m = 0.42 ??????? I do not understnd this 

You have been given two carbon fibre composite materials made
using Intermediate Modulus carbon fibres and a toughened epoxy
matrix; the first is a unidirectional material containing 36±2% by
weight of resin and the second reinforced with a 200gm-2 balanced 2
x2 twill weave fabric. The cured ply thickness of the UD material is
0.14mm and that of the fabric 0.2mm. The fibre strength (o,) =
5,500MPa, fibre modulus (E₁) = 290GPa and density (p₁) = 1.8gcm-³.
The matrix has a strength (om) = 50MPa, modulus (Em) = 4.5GPa and
density (Pm) = 1.3gcm-³.
The materials are to be used to design and manufacture a steering
track rod for a prototype sports car. The track rod is to be fitted with
spherical bearings either end. It will be of circular cross-section with
an outer diameter of 10mm and length of 450mm. Maximum tensile
load is predicted to be 11kN and that in compression 2kN. Assuming
the compressive loading upon the laminate to be negligible, design a
laminate able to provide a reserve factor of 2.0 (As a hint; treat the
tube as a flat plate then apply the reserve load)
Transcribed Image Text:You have been given two carbon fibre composite materials made using Intermediate Modulus carbon fibres and a toughened epoxy matrix; the first is a unidirectional material containing 36±2% by weight of resin and the second reinforced with a 200gm-2 balanced 2 x2 twill weave fabric. The cured ply thickness of the UD material is 0.14mm and that of the fabric 0.2mm. The fibre strength (o,) = 5,500MPa, fibre modulus (E₁) = 290GPa and density (p₁) = 1.8gcm-³. The matrix has a strength (om) = 50MPa, modulus (Em) = 4.5GPa and density (Pm) = 1.3gcm-³. The materials are to be used to design and manufacture a steering track rod for a prototype sports car. The track rod is to be fitted with spherical bearings either end. It will be of circular cross-section with an outer diameter of 10mm and length of 450mm. Maximum tensile load is predicted to be 11kN and that in compression 2kN. Assuming the compressive loading upon the laminate to be negligible, design a laminate able to provide a reserve factor of 2.0 (As a hint; treat the tube as a flat plate then apply the reserve load)
i. Calculate V₁ for each of the materials;
UD material W=0.36 → W₁= 0.64
V₁ =
Wf
W₁ + Wm
V₁
Pc
Pm²
V₁ =
Fabric Material; W = 0.42 → W₁ = 0.58
Wf
W₁
+ Wm (Pc)
Pm
0.64
1.8
0.64 +0.36 (13)
Vf
0.58
0.58+0.42 (13)
1.8
= 0.56
= 0.50
Transcribed Image Text:i. Calculate V₁ for each of the materials; UD material W=0.36 → W₁= 0.64 V₁ = Wf W₁ + Wm V₁ Pc Pm² V₁ = Fabric Material; W = 0.42 → W₁ = 0.58 Wf W₁ + Wm (Pc) Pm 0.64 1.8 0.64 +0.36 (13) Vf 0.58 0.58+0.42 (13) 1.8 = 0.56 = 0.50
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