[x y​]+[w z​]=[x+2w y−2z​]α[x y​]=[αx αy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? [xy​]+[wz​]=[x+2wy−2z​]α[xy​]=[αxαy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? a. No, because though the Additive Inverse axiom is satisfied, the Commutative is not satisfied b. Yes, because all 10 vector space axioms are satisfied c. No, because the One axiom is not satisfied, though the Zero and Additive clousre are satisfied d. No, because neither the Zero axiom nor the Additive Inverse axiom is satisfied e. No, because the Additive Inverse axiom is not satisfied, though the Commutative is satisfied f. No, because the Additive Closure axiom is not satisfied, though the Scalar multiplication is satisfied g. No, because though the Additive Closure axiom is satisfied, the Scalar multiplication is not satisfied h. No, because neither the Zero axiom nor the One axiom is satisfied

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 59E
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[x y​]+[w z​]=[x+2w y−2z​]α[x y​]=[αx αy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? [xy​]+[wz​]=[x+2wy−2z​]α[xy​]=[αxαy​]​ Where x,y,z,w and α are in C. Is V a vector space over the field of Complex numbers? Why or why not? a. No, because though the Additive Inverse axiom is satisfied, the Commutative is not satisfied b. Yes, because all 10 vector space axioms are satisfied c. No, because the One axiom is not satisfied, though the Zero and Additive clousre are satisfied d. No, because neither the Zero axiom nor the Additive Inverse axiom is satisfied e. No, because the Additive Inverse axiom is not satisfied, though the Commutative is satisfied f. No, because the Additive Closure axiom is not satisfied, though the Scalar multiplication is satisfied g. No, because though the Additive Closure axiom is satisfied, the Scalar multiplication is not satisfied h. No, because neither the Zero axiom nor the One axiom is satisfied

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