X STARTING AMOUNT 0.400 0.400 L x 0.350 mol KBr 1 L X = 16.7 g KBr 0.350 1 mol KBr X What is the mass in grams of KBr in 0.400 L of a 0.350 M solution? = 16.7 ADD FACTOR 0.400 0.140 5.47 16.7 mol KBr g KBr DELETE mL ㅗㅜ 39.10 6.022 x 1023 1 1.18 x 10³ M KBr L ANSWER 0.350 136 9.60 × 10³ RESET 7.09 x 1020 8.43 x 10²² g KBr 2 g KBr/mol 119

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Chapter15: Solutions
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Problem 105AP
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Question
0.400
✓
STARTING AMOUNT
0.400 L X
0.350 mol KBr
1 L
X
16.7 g KBr
0.350
mol KBr
✓
What is the mass in grams of KBr in 0.400
=
ADD FACTOR
x( )
X
0.400
0.140
16.7
5.47
16.7
mol KBr
g KBr
mL
DELETE
X
A
39.10
1
6.022 × 1023
1.18 × 10-³
M KBr
L
L of a 0.350 M solution?
ANSWER
0.350
136
7.09 × 102⁰
9.60 × 10-³
g KBr
RESET
3
8.43 × 10²²
g KBr/mol
119
Transcribed Image Text:0.400 ✓ STARTING AMOUNT 0.400 L X 0.350 mol KBr 1 L X 16.7 g KBr 0.350 mol KBr ✓ What is the mass in grams of KBr in 0.400 = ADD FACTOR x( ) X 0.400 0.140 16.7 5.47 16.7 mol KBr g KBr mL DELETE X A 39.10 1 6.022 × 1023 1.18 × 10-³ M KBr L L of a 0.350 M solution? ANSWER 0.350 136 7.09 × 102⁰ 9.60 × 10-³ g KBr RESET 3 8.43 × 10²² g KBr/mol 119
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