What is the answer Evaluate f(-6), f (2), f (3), and f (5).√x² ++5=f(x)==f(-6) 14; f(2)= -10; f(3) = 14; f(5)= 30f(-6) 14; f(2)= 9; f(3) = 14; f(5) = 30f(-6)= -22; f(2)= 9; f(3) = 14; f(5) = -30f(-6)= -22; f(2)= 10; f(3) = -14; (5)= 30x>2-3x-4x≤2

Answered: Image /qna-images/answer/da76b2f1-2a3a-43a9-8122-0891d1bb0261.jpg

[x² +5 = x > 2 f(x)= -3x-4 f(-6) 14; f(2)= -10; f(3) = 14; f(5) = 30 f(-6) 14; f(2)= 9; f(3) = 14; f(5) = 30 f(-6)= -22; f(2)= 9; f(3) = 14; f(5) = -30 f(-6)= -22; f(2)= 10; f(3) = -14; f(5)= 30 x≤2

[x² +5 = x > 2 f(x)= -3x-4 f(-6) 14; f(2)= -10; f(3) = 14; f(5) = 30 f(-6) 14; f(2)= 9; f(3) = 14; f(5) = 30 f(-6)= -22; f(2)= 9; f(3) = 14; f(5) = -30 f(-6)= -22; f(2)= 10; f(3) = -14; f(5)= 30 x≤2

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter5: Factoring Polynomials

Section5.4: Multiplying Binomials Mentally

Problem 4E

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Question

What is the answer

Evaluate f(-6), f (2), f (3), and f (5).
√x² +
+5
=
f(x)=
=
f(-6) 14; f(2)= -10; f(3) = 14; f(5)= 30
f(-6) 14; f(2)= 9; f(3) = 14; f(5) = 30
f(-6)= -22; f(2)= 9; f(3) = 14; f(5) = -30
f(-6)= -22; f(2)= 10; f(3) = -14; (5)= 30
x>2
-3x-4
x≤2

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