with the given table below, find the following: - Linear Error of Closure - Relative Error of Closure - BSE Bearing Distance Lat Dep cLat cDep AdjLat AdjDep AB S 68 5 35 W 472.68 -176.36 -438.55 45.67633474 45.67926201 -130.68 -392.87 BC N 19 46 0 W 216.3 73.09 -203.40 20.88522093 20.8865594 93.98 -182.51 CD N 45 55 20 E 276.52 192.35 198.65 26.72086842 26.72258088 219.08 225.37 DA S 54 59 15 E 382.24 -219.31 313.06 36.93687525 36.93924243 -182.38 350.00 1347.57 ∈latitude=el=-130.22
with the given table below, find the following: - Linear Error of Closure - Relative Error of Closure - BSE Bearing Distance Lat Dep cLat cDep AdjLat AdjDep AB S 68 5 35 W 472.68 -176.36 -438.55 45.67633474 45.67926201 -130.68 -392.87 BC N 19 46 0 W 216.3 73.09 -203.40 20.88522093 20.8865594 93.98 -182.51 CD N 45 55 20 E 276.52 192.35 198.65 26.72086842 26.72258088 219.08 225.37 DA S 54 59 15 E 382.24 -219.31 313.06 36.93687525 36.93924243 -182.38 350.00 1347.57 ∈latitude=el=-130.22
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
with the given table below, find the following:
- Linear Error of Closure
- Relative Error of Closure
- BSE
Bearing |
Distance |
Lat |
Dep |
cLat |
cDep |
AdjLat |
AdjDep |
|
AB |
S 68 5 35 W |
472.68 |
-176.36 |
-438.55 |
45.67633474 |
45.67926201 |
-130.68 |
-392.87 |
BC |
N 19 46 0 W |
216.3 |
73.09 |
-203.40 |
20.88522093 |
20.8865594 |
93.98 |
-182.51 |
CD |
N 45 55 20 E |
276.52 |
192.35 |
198.65 |
26.72086842 |
26.72258088 |
219.08 |
225.37 |
DA |
S 54 59 15 E |
382.24 |
-219.31 |
313.06 |
36.93687525 |
36.93924243 |
-182.38 |
350.00 |
1347.57 |
∈latitude=el=-130.22 |
∈departure=ed=-130.23 |
130.2192993 |
130.2276447 |
0.00 |
0.00 |
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