With E1 = 15 Volts, E2 = 10 Volts, R1 = 4.7 k2, R2 = 6.8 k and R3 = 15 kn, fin the nodal voltage at A.
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- 201503131 3. Two batteries with E, = 3V and E₂ = 5 V are connected with three resisters R₁ = 10 ohms, R₂ = 20 ohms and R3 = 30 ohms as shown in the Figure. (8-points) a) Find the currents I₁, I2 and 13 passing through the resistors R₁, R₂ and R3 consecutively and indicate their directions in the figure. (4-points) I Iz V.P 23 13 = I₁+I₂ R₂ 10 3 & 3-101₁-3013 =0 5-20 I 2-10 I₁ = 0 I R₁ ww R3 30 20 25(b) For a configuration as shown in Figure Q1(b), determine the current through 402 resistor, l4on 300 400 200 500 600 700 SA 100 800 900 Figure Q1(b)In the figure the ideal batteries have emfs ɛ1 = 20.4 V, ɛ2 = 9.05 V, and ɛ3 = 5.40 V, and the resistances are each 2.40 Q. What are the (a) size and (b) direction (left or right) of current i,? (c) Does battery 1 supply or absorb energy, and (d) what is its power? (e) Does battery 2 supply or absorb energy, and (f) what is its power? (g) Does battery 3 supply or absorb energy, and (h) what is its power? (a) Number i Units (b) (c) (d) Number i Units (e) (f) Number i Units (g) (h) Number i Units
- Mid-term exam Principles of Electricity (cont'd) 11. According to Ohm's Law, electron flow is proportional to electrical pressure. a. Inversely b. Indirectly c. Directly d. Not 12. What equation represents the characteristics of electron flow in a parallel circuit? a. E=IxR b. ET=E1=E2=E3... c. IT=l1+l2+l3... d. ET=E1+E2+E3... 13. What equation represents the characteristics of electrical pressure in a parallel circuit? a. E=IxR b. ET=E1=E2=E3... c. IT=l1+l2+l3... d. ET=E1+E2+E3.. 14. How much electrical pressure would be required to produce 25A current in a circuit with 19.20 total resistance? a. 480A b. 480V C. 1.3V d. 0.768V 15. As resistors are removed from a series circuit, what will happen to the current? a. The current will increase b. The current will decrease c. The current will stay the same d. There is not enough information givenIn the figure the current in resistance 6 is i = 1.43 A and the resistances are R₁ = R₂ = R3 = 1.68 2, R₂ = 15.1 Q2, R5 = 7.41 Q2, and R6 = 4.57 2. What is the emf of the ideal battery? E www R₁ O a. 25.7V O b. 52.3 V O C. 47.2 V O d. 21.4 V O e. 6.54 V R3 www R₂ www R₁ R₂ 16 R6Suppose the three branch currents in this circuit are I₁ = -3 A, I₂ = -18 A, and I3 = -15 A. The voltage drop across each circuit element is as given in the table below. From this information, determine, for each of these circuit elements, (i) whether an active or passive sign convention is being used for that element, (ii) whether that element is absorbing or producing a net (positive) amount of electrical power. In each answer box within the table below, type the correct choice from among the bold-faced words above. V₂ B A B A C D 1₁ A B 1₂ 1₂ + Circuit element Voltage drop Sign convention? Absorbing or producing net electrical power? -9 V -2 V C 9 V -11 V D
- Figure 2.1 shows a simple circuit. Explain why using a DMM tomeasure the DC voltage across resistor R2 might lead to inaccurate results. Include in your answer how the value of R2 might affect the size of the error and provide some circuit diagrams and equations to showhow to calculate the error.Eлample (1) For the series-parallel arrangement shown in Figure below, find: a) The supply current. I ?. b) The current flowing through each resistor. c) The p.d. across each resistor. R3 2.50 40 Ri R4 RE I ? 200VPT of INST1=2s. PT of INST2=4s. S1 is switched at t=0s. S2 is switched at t=3s. * INST1 TON INST2 $1 S2 TON IN IN PT ET PT ET- 2s 5s 7s 6s 4s ET1=2s at ET2=2s at Energizing time for L
- A 2 wire d.c. ring distributor is fed at A with 220 V. The various loads are 10A at B, 20A at C,30A at D and 10A at E. The resistances of the sections AB, BC, DC, DE and EA are 0.1 £2, 0.05 $2, 0.01 2, 0.025 2 and 0.075 respectively. Determine, a. Point of minimum potential b. Current in each section [Ans.: Point C, 29.04 A, 19.04 A, 0.96 A, 30.96 A and 40.96 AThe voltage source V1= 250 V with internal resistance R1= 2ohm in Figure 2.1 will feed the RL resistor with a transformer with a conversion ratio of 1/16 and considered ideal. What should be the value (RL) of the RL resistor to be placed so that the RL resistor can draw maximum power from the voltage source? What is the power (Pvi) consumed by the voltage source when the RL resistor you found is active? In this case, how much power (Pri) is spent on the internal resistance of the source, the resistor R1?RL=Pv=PRI =Problem A potentiometer is an instrument for measuring an unknown voltage in comparison to a standard voltage. In the potentiometer shown in Figure 1.0 a 16.0-m stretch of wire AB is connected to a 9.00-V battery. The resistance per unit length of the wire is 16.0 0/mm. The movable contact P is at point B. An ammeter (circle with A inside) is connected to point A. 16.0 m A B www Figure: 1.0 A V = 9.00 V