Which statement is false? An auxotrophic mutant requires at least one nutrient for growth Bacterial conjugation requires cell-to-cell contact An Hfr is an E. coli strain with an F factor integrated into bacterial genome Bacterial transformation is the conversion of a prokaryotic cell into a eukaryotic cell

Which statement is false? An auxotrophic mutant requires at least one nutrient for growth Bacterial conjugation requires cell-to-cell contact An Hfr is an E. coli strain with an F factor integrated into bacterial genome Bacterial transformation is the conversion of a prokaryotic cell into a eukaryotic cell

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter15: From Dna To Protein

Section15.1: The Connection Between Dna, Rna, And Protein

Problem 1SB

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A series of auxotrophic mutants were isolated in Neurospora. Examination of fungi containing these mutations revealed that they grew on minimal medium to which various compounds (A, B, C, D) were added; growth responses to each of the four compounds are presented in the following table. Give the order of compounds A, B, C, and D in a biochemical pathway. Outline a biochemical pathway that includes these four compounds and indicate which step in the pathway is affected by each of the mutations. Compound Mutation number А в С A D 134 276 987 773 772 146 333 123 + + I +
TRY TO KEEP IN SHORT AND USE OWN WORD FOR THIS QUESTION You are studying a type of bacteria isolated from the acidic water runoff of a mining operation. You subject two batches of the same bacteria type to different environmental growth conditions. One batch is grown at pH 2, while the other is grown at pH 7. All other environmental parameters are kept identical between the two batches. You then collect their proteins and run a Western blot using an antibody that binds to a proton efflux pump protein (which actively expends energy to pump protons out of a cell). How would you characterize the information obtained in this experiment? What does it tell you, and why is that potentially valuable information?
A pure culture of an unknown bacterium was streaked onto plates of a variety of media. You notice that the colony morphologyis strikingly different on plates of minimal media with glucose compared to that seen on trypticase soy agar plates. How can you explain these differences in colony morphology? Also, describe what happens when a nonsense mutation is introduced into the gene encoding transposase within a transposon and why is it more likely that insertions or deletions will be more detrimental to a cell than point mutations?
The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was 10mm or greater, the result is listed as ++. In the lab, the MGC instructors plated all 6 of the ESKAPE pathogen safe relatives on LB agar plates. Then we patched Unknown Bacteria 5 from a Master plate onto the safe relative. The results are shown here: METRIC METRIC METRIC 1 B. subtilis S. epidermidis E. coli Complete the final column (Unknown Bacteria 5) of the table by selecting -, +, or ++ using the criteria in the…
The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was greater than 10mm, the result is listed as ++. Page 50 in your research guide states: "Some antibiotics are broad spectrum, meaning that they affect a wide range of bacteria. Other antibiotics have a narrow spectrum of activity. One anatomical feature that plays a significant role in the susceptibility of a microbe to a particular antibiotic is its cell wall composition (discussed in Section 8)". Research the cell wall…
Fifteen bacterial colonies growing on a complete medium (that means that they have all of nutrients that they need supplied in the dish, and they don't actually need to synthesize these compounds to survive) are transferred to minimal medium. Twelve of the colonies grow on minimal medium. Three colonies do not grow on minimal medium. But, if these three colonies are put on a plate that has minimal medium supplemented with the amino acid serine (min + Ser), they all What does this suggest about the three bacterial colonies (pick all that apply)? grow. They lack the ability to synthesize their own serine. O They are probably wild-type. They probably have a mutation that causes them to lack a certain protein. They probably have a mutation that causes them to be unable to perform translation. O They probably have a mutation that causes them to be unable to perform transcription. O They are able to synthesize everything that they need to grow except for serine.
The synthesis of arginine by Nuerospora was determined by examining a number of mutant strains that were unable to synthesize the compound. Use the table of bacterial growth below to 1) determine the correct sequence of the synthesis pathway and 2) where in the synthesis pathway each mutation interrupts the synthesis. A “+" indicates growth. Nothing added to Succinate Ornithine added Strain Cirtulline Arginine Added added added growth medium Wild Mutant 1 Mutant 2 Mutant 3 Mutant 4
The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was greater than 10mm, the result is listed as ++, Page 50 in your research guide states: "Some antibiotics are broad spectrum, meaning that they affect a wide range of bacteria. Other antibiotics have a narrow spectrum of activity. One anatomical feature that plays a significant role in the susceptibility of a microbe to a particular antibiotic is its cell wall composition (discussed in Section 8)". Research the cell wall…
Three pairs of bacterial cells with the given genotypes undergo conjugation. Place match the genotype of each cell after conjugation to its initial genotype. F+ x F Hfr F- F' F- Answer Bank F F F+ Hfr What is the role of the F-factor in conjugation? It contains genes necessary for replication of the donor's F plasmid. can occur. It allows auxotrophic bacterial cells to survive on minimal medium so that conjugation It contains genes that force recombination between the donor and recipient chromosomes. It contains genes necessary for the formation of the pilus. O It degrades the chromosome of the recipient cell after conjugation.
Conjugation depends on direct cell-to-cell contactbetween a donor F+ carrying either a conjugative________ (the F plasmid) or an integrated conjugativeelement (as in Hfr strains), and a recipient lacking suchan element (F−).
Antibiotics that target bacterial molecules not previously exploited are desperately needed. One such target is the protein FtsZ. The small molecule 3-methoxybenzamide (3-MBA) is known to inhibit FtsZ in Bacillus subtilis but is not bacteriocidal. Nonetheless, researchers reasoned that 3-MBA offered a good starting point for the synthesis of a molecule that might be a potential drug candidate. Over 500 3-MBA analogues were synthesized and screened; one called PA190723 was extremely potent in its capacity to bind FtsZ and inhibit bacterial growth. In fact, when used in a mouse model, PA190723 was bacteriocidal against methicillinand multidrug-resistant Staphylococcus aureus. What makes FtsZ a good drug target? What preliminary information about 3-MBA would be helpful if you were designing the 3-MBA analogues? As these researchers move forward with clinical (human) testing, what other parameters and outcomes must be assessed besides the bacteriocidal activity of PA190723?
In Figure 6-13, explain at the protein level why this heterokaryon can grow on minimal medium