Which of the following option is correctly matched Equivalent pattern 1. [^ 0-9] 2. [0-9] 3. [\r\t\n\f] 4. [A-Z a-z_0-9] Name (p) \d (q) \D (r) \w (s) \s Р-2, q-1, г-3, s-4 O P-1, q-1, r-3, s-4 Р-2, 9-1, г-4, s-3 O P-1, q-2, r-4, s-3 O None of these
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Don't copy the answer from Bartleby do your own even if you write on papper also no problem
![Which of the following option is correctly matched
Equivalent pattern
1. [^ 0-9]
2. [0-9]
3. [r\t\n\f]
4. [A-Z a-z_0-9]
Name
(p) \d
(q) \D
(r) \w
(s) \s
Р-2, q-1, г-3, s-4
O P-1, q-1, r-3, s-4
P-2, q-1, r-4, s-3
Р-1, 9-2, г-4, s-3
O None of these](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F251dbf4b-058e-4f24-a9ec-f9adcd9ba31f%2F1fe023e0-1b3d-4315-b54f-5be5ed733e92%2F7hmhyqv_processed.jpeg&w=3840&q=75)
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Solved in 2 steps
- Fix the following code:Dim dblRegularPay As DoubleDim dblOvertimePay As DoubleintRegularPay = 783.87intOvertimePay = 105.92lbl.TotalPay = (dblRegularPay + dblOvertimePay).ToString ('C')WebConnect 3270 Sphinx of Hatsheps... - Question Completion Status: Based on this information, complete the code for numbered region 3. QUESTION 10 ("Enter a number:")) Fill each of the numbered areas so that the code you create asks the user to enter a whole number using the keyboard and store that number into variable x. QUESTION 11 if(x<0 or x10): print("Invalid number! ") The piece of code above checks whether x is between 0 and 10, If not it prints a text. ClickNew Jave code must be entered inbetween grey blocks of code as seen in photo
- The compound condition A ^ B will be true if: (circle all correct answer or answers)a. Both A and B true; b. Both A and B false; c. A true and B false; d. B true and A falseReplace all the 0 (Zero) digits in your ID by 4. Example: If your ID is 382200448 , it becomes 382244448 Take the first 6 digits and substitute them in this expression (( A + B) / C) * ((D-E)/F)-2) according to the following table; [1 mark] Letter Replace by Digit Example Digit A 1st 3 B 2nd 8 C 3rd 2 D 4th 2 E 5th 4 F 6th 4 After substitution your expression ? Draw a rooted tree that represents your expression. [3 marks] What is the prefix form of this expression. [3 marks] What is the value of the prefix expression obtained in step 2 above? [3 marks]• L₂ = {w = {a,b,c}* | w = b(a\b \cb)*a}
- Let \vec a= [1, 2, 3, 4, 5], \vec b= [0, 1, 0, 1, 0] What is 3* \vec b ? Be careful about the format.Lines of code can only be added inbetween gery lines of code. ie, lines 12-14.def read_flights(flights_source: TextIO, routes: RouteDict) -> FlightDir: """Return the flights from flights_source, including only the ones that have an entry in routes. >>> from io import StringIO >>> flight_src = StringIO(TEST_FLIGHTS_SRC) >>> actual = read_flights(flight_src, TEST_ROUTES_DICT_FOUR_CITIES) >>> actual == TEST_FLIGHTS_DIR_FOUR_CITIES True """ flights = [] src_index = FLIGHT_DATA_INDEXES["Source airport"] dst_index = FLIGHT_DATA_INDEXES["Destination airport"] # Complete this function. for line in routes_source:
- Her.e Provide the correct c++ code for below code /****************************************************************************** Welcome to GDB Online. GDB online is an online compiler and debugger tool for C, C++, Python, Java, PHP, Ruby, Perl, C#, OCaml, VB, Swift, Pascal, Fortran, Haskell, Objective-C, Assembly, HTML, CSS, JS, SQLite, Prolog. Code, Compile, Run and Debug online from anywhere in world. *******************************************************************************/ #include using namespace std; #include int hextodec(char num[]) { int len = strlen(num); int base = 1; int temp = 0; for (int i=len-1; i>=0; i--) { if (num[i]>='0' && num[i]='A' && num[i].Let L=(aa, ab, baa). True or false: baaaaab is in L^? Select one: O True O FalseThe caret when found at the start of a character set, is the equivalent to "not" in RegEx. The regular expression [^a-c] matches any characters except "a", "b" and "c". Write the regular expression that matches any characters except letters, digits and spaces. You must use a negated character set in your expression. Examples txt = alice15@gmail.com " pattern = "yourregularexpressionhere" re.findall(pattern, txt) ["@", "."] Notes • You don't need to write a function, just the pattern. • Do not remove import re from the code. • Find more info on RegEx and negation in Resources. • You can find all the challenges of this series in my Basic RegEx collection.