When 12.10g of MTBE (methyl tert-butul ether) is burned in a combustion apparatus with oxygen, it forms 30.20g of CO2 and 14.80g of H20. Given the compound molar mass (88.17)g/mol - what is the Molecular Formula of the compound ?
When 12.10g of MTBE (methyl tert-butul ether) is burned in a combustion apparatus with oxygen, it forms 30.20g of CO2 and 14.80g of H20. Given the compound molar mass (88.17)g/mol - what is the Molecular Formula of the compound ?
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 67QAP: When potassium chlorate is subjected to high temperatures, it decomposes into potassium chloride and...
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When 12.10g of MTBE (methyl tert-butul ether) is burned in a combustion apparatus with oxygen, it forms 30.20g of CO2 and 14.80g of H20. Given the compound molar mass (88.17)g/mol - what is the Molecular Formula of the compound ?
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