The molality of ethyl alcohol in a solution of water (H2O, MW = 18.02 g/mol) and ethanol (C2H5OH, MW = 46.08 g/mol) is mE = 0.376 mol/kg. Based on this information find XE (mol fraction of ethyl alcohol) and the percent by mass ethyl alcohol in the solution
The molality of ethyl alcohol in a solution of water (H2O, MW = 18.02 g/mol) and ethanol (C2H5OH, MW = 46.08 g/mol) is mE = 0.376 mol/kg. Based on this information find XE (mol fraction of ethyl alcohol) and the percent by mass ethyl alcohol in the solution
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section: Chapter Questions
Problem 133QRT
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The molality of ethyl alcohol in a solution of water (H2O, MW = 18.02 g/mol) and ethanol (C2H5OH,
MW = 46.08 g/mol) is mE = 0.376 mol/kg. Based on this information find XE (mol fraction of ethyl
alcohol) and the percent by mass ethyl alcohol in the solution
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When finding out the moles of water, why is the denominator of that 18.02? Wouldnt it be the other way around and have the denominator be 1000g?
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