When 116.g of glycine C2H5NO2 are dissolved in 1050.g of a certain mystery liquid X, the freezing point of the solution is 7.2°C lower than the freezing point of pure X. On the other hand, when 116.g of potassium bromide are dissolved in the same mass of X, the freezing point of the solution is 8.4°C lower than the freezing point of pure X.Calculate the van't Hoff factor for potassium bromide in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits. i=
When 116.g of glycine C2H5NO2 are dissolved in 1050.g of a certain mystery liquid X, the freezing point of the solution is 7.2°C lower than the freezing point of pure X. On the other hand, when 116.g of potassium bromide are dissolved in the same mass of X, the freezing point of the solution is 8.4°C lower than the freezing point of pure X.Calculate the van't Hoff factor for potassium bromide in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.
i=
Answer:-
this question is answered by using the simple concept of depression in freezing point . Firstly molal freezing point constant is calculated then Van't Hoff factor is calculated.
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