What volume (mL) of 0.0665 M KMnO4 is necessary to convert 12.5 g KI (166.00 g/mol) to I2 in the reaction [2KMnO4 + 10KI + 8H2SO4 ( 6K2SO4 + 2MnSO4 + 5I2 + 8H2O]. Assume that H2SO4 is present in excess.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.68QE
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What volume (mL) of 0.0665 M KMnO4 is necessary to convert 12.5 g KI (166.00 g/mol) to I2 in the reaction [2KMnO4 + 10KI + 8H2SO4 ( 6K2SO4 + 2MnSO4 + 5I2 + 8H2O]. Assume that H2SO4 is present in excess. 

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