What is wrong in the following method in JAVA?
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What is wrong in the following method in JAVA?
public class Test {
public static void main(String[] args) {
xMethod(1234567);
}
public static void xMethod(double n) {
if (n != 0) {
System.out.print(n);
xMethod(n / 10);
}
}
}
Step by step
Solved in 4 steps with 2 images
- import java.util.Scanner; public class Application {public static void main(String[] args){ int Num;float Ave;Employee[] Emp = new Employee[100]; System.out.println("Enter the number of employees:");Num = Integer.parseInt(new Scanner(System.in).nextLine());for (int i = 0; i < Num; i++){ Emp[i] = new Employee();Emp[i].Input();} System.out.printf("The list of employees:");System.out.println();Display(Emp, Num);Ave= AverageSalary(Emp, Num);System.out.printf("\nAverage salary is:" + "%.2f", Ave); System.out.printf("\nThe employee with highest salary is:\n" + employeeHigh(Emp, Num));}private static float AverageSalary(Employee [] emps, int n){float sum=0; for (int i = 0; i < n; i++)sum = sum + emps[i].salary;return sum/n;}private static void Display(Employee[] arr, int n){ for (int i = 0; i < n; i++){System.out.printf("%s",arr[i]);}}private static Employee employeeHigh(Employee[] arr, int n){ float high= arr[0].salary ;int iHigh = 0;for (int i = 1; i < n; i++){if( arr[i].salary…public class Test { public static void main(String[] args) { int n = 13; while (n <= 5) { method1(n); n++; } } public static void method1(int num) { for (int i System.out.print("*"); } System.out.println(); //start a new line } 1; i <= num; i++) {Analyze the following code: public class Test{ public static void main(String[] args) { int[] x = {0, 1, 2, 3, 4, 5); xMethod(x, 5); } } public static void xMethod (int[] x, int length) { for (int i = 0; iAnalyze the following code:public class Test { public static void main(String[] args) { int[] x = {0, 1, 2, 3, 4, 5}; xMethod(x, 5); } public static void xMethod(int[] x, int length) { for (int i = 0; i < length; i++) System.out.print(" " + x[i]); }} The program displays 0 1 2 3 4 5 and then raises a runtime exception. The program displays 0 1 2 3 4 and then raises a runtime exception. The program displays 0 1 2 3 4. The program displays 0 1 2 3 4 5.please help me public static void main(String args[]){ int[] x={1,4,88,9,13,77,4,18}; for(int i=0;i<x.length;i++){ for( int j=i+1;j<x.length;j++){ if(x[i]==x[j]){ System.out.println("duplicates exists is : "+x[i]); }}} System.out.println("no duplication"); } The above segment of code is searching the duplicated values inside an array, where the complexity is O(n). Suggest another solution for the above problem with less time complexity.import java.util.Scanner; public class LabProgram {public static void main(String[] args) {Scanner sc = new Scanner(System.in); int n = sc.nextInt();// Validating the inputif(n >= 20 && n <= 98) {// Running the countdownwhile(true) {System.out.print(n + " "); // Displaying the current value of the countdown// If the digits are the same,if(areDigitsIdentical(n)) {break; // Breaking out from the loop}// Decreasing the value of the countdownn--;System.out.println("");}} else {System.out.println("Input must be 20-98"); // Displaying the appropriate message for InValid Input}}public static boolean areDigitsIdentical(int n) {int d0 = n % 10; // Extracting out the 1st digitint d1 = n / 10; // Extracting out the 2nd digit// If the two digits are the same,if(d0 == d1)return true; // Return trueelse // Otherwise,return false; // Return false}} The language is Java. The output has to print a space after each number including the last one (The pictures shown is what the code needs…10. public static void methodl (int i, int num) { for (int j = 1; j <= i; j++) { " "); System.out.print (num + num *= 2; } System.out.println(); } public static void main(String[] args) { int i = 1; while (i <= 6) { methodl (i, 2); i++; }. Find the output of the following code. Public class Solution{ Public static void main(String args[]){ Int i; for(i 1; i 3) continue; } System.out.println(i); }public class ReversedDigit { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("Please enter a number: "); int number = scan.nextInt(); int reversedNumber = 0; do { reversedNumber = number%10; number = number/10; } while (number > 0); }} Modify the coding example, to count what is the total of all digits of a number. For example, when user enters 301, your output is 4 because 3+0+1=4; when user enters 5116, your output is 13 (5+1+1+6 = 13).Analyze the following code.public class Test { public static void main(String[] args) { System.out.println(m(2)); } public static int m(int num) { return num; } public static void m(int num) { System.out.println(num); }} What can you say about the above code? Does it run? Does it compile? Any output?Identify 2 errors in this code: public class Test { public static void main(String[] args) { nPrintln(5, "Welcome to Java!"); } public static void nPrintln(String message, int n) { for (int i = 0; i < n; i++) { System.out.println(message); } return n; }}import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println("*".repeat(currentLength) + " "); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength) + " "); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public static…SEE MORE QUESTIONS