What is the size in bits of the tag in the cache?
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- Consider a four-way set associative cache comprised of 64-bit words. The number of sets is 4096 and the number of words per line is 8. What is the size of the cache?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache: Tag Index Offset 31-10 9-6 5-0 1. What is the cache block size (in words)? 2. How many entries does the cache have? 3. What is the ratio between total bits required for such a cache implementation over the data storage bits?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag 31-10 Index 9-5 a. What is the cache block size (in words)? b. How many entries does the cache have? Offset 4-0 c. What is the ratio between total bits required for such a cache implementation over the data storage bits?
- Consider a direct mapped cache that holds 1024 words, has a block size of one word, and uses 32-bit addresses. How many bits are in the tag?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. What is the ratio between total bits required for such a cache implementation over the data storage bits?For a direct-mapped cache design with a 32-bit address, the following bitsof the address are used to access the cache. Use the table below. a. What is the cache block size (in words)?b. How many entries does the cache have?c. What is the ration between total bits required for such a cache implementation overthe data storage bit?
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have? Tag Index Offset Block offset | Byte offset 31–12 11-6 5-2 1-0For a direct-mapped cache design with a 32-bit address, the following bits of the address areused to access the cache.Tag Index Offset31–10 9–6 5–0a– What is the cache block size (in words)? b – How many entries does the cache have? c – What is the ratio between total bits required for such a cache implementation overthe data storage bits?A cache memory system with capacity of N words and block size of B words is to be designed. If it is designed as a direct mapped cache, the length of the TAG field is 14 bits. If it is designed as a 4-way set associative cache, the length of the TAG field will be ………… bits.
- A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.Consider a 32-bit physical memory space and a 32 KiB 2-way associative cache with LRU replacement. You are told the cache uses 5 bits for the offset field. Write in the number of bits in the tag and index fields. Tag length in bits = Index length in bits =For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have?