What is the ratio of A / HA in for the buffer chosen for part C before adding acid or base? How many moles of A and HA are present in the solution? Remember that the volume used was 50mL. I

Chemistry: Principles and Reactions
8th Edition
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Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 32QAP: Enough water is added to the buffer in Question 30 to make the total volume 5.00 L. (a) Calculate...
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need help with questions 2-4.
Buffer Chosen:
PART C: Why is a buffer a buffer?
Water
Sodium Citrate
pH before addition of acid or base
4.76
6.13
Did you add acid or base?
Acıd
Acid
pH after the addition of acid or base
473
2.11
Net change in pH
0.03
4.02
2. What is the ratio of A / HA in for the buffer chosen for part C before adding acid or base? How
many moles of A and HA are present in the solution? Remember that the volume used was
50mL. I
3. Calculate the theoretical pH of the buffer chosen for Part C after adding 0.5mL of 1M HCI or
NaOH.
0.0005mol if HCL is completely dissociated
Initial moles: 51.3 x 50ml=
4. Calculate the % error between the theoretical pH and measured pH (the one recorded in the
table) of the buffer in Part C after adding 0.5ml, of 1M HCl or 1M NAOH
Transcribed Image Text:Buffer Chosen: PART C: Why is a buffer a buffer? Water Sodium Citrate pH before addition of acid or base 4.76 6.13 Did you add acid or base? Acıd Acid pH after the addition of acid or base 473 2.11 Net change in pH 0.03 4.02 2. What is the ratio of A / HA in for the buffer chosen for part C before adding acid or base? How many moles of A and HA are present in the solution? Remember that the volume used was 50mL. I 3. Calculate the theoretical pH of the buffer chosen for Part C after adding 0.5mL of 1M HCI or NaOH. 0.0005mol if HCL is completely dissociated Initial moles: 51.3 x 50ml= 4. Calculate the % error between the theoretical pH and measured pH (the one recorded in the table) of the buffer in Part C after adding 0.5ml, of 1M HCl or 1M NAOH
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