What is the output of the following code segments (when nun independently)? int [] myAry = {10,20,30,40,50}; for (int x=0; x<=myAry.length-1; x++ ) System.out.print(" "+ myAry[x] );
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- #include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }int X[10]={2,0,6,11,4,5,9,11,-2,-1); From the code above, what is the value of X[8] ?#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.
- int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?
- include<stdio.h> #include<stdlib.h> int main() { int N; scanf("%d", &N); int input[N], ind, rem; for(ind=0;ind<N;ind++) scanf("%d", &input[ind]); // 8 7 6 4 int two_digits[22], two_digits_ind; unsignedlonglongint res = 0; two_digits[0] = 1; for(two_digits_ind=1;two_digits_ind<22;two_digits_ind++) two_digits[two_digits_ind] = ((two_digits[two_digits_ind-1])*2)%100; for(ind=0;ind<N;ind++) { if(input[ind]>21) { rem = input[ind] % 22; rem += 2; } else rem = input[ind]; res = res + two_digits[rem]; } printf("%llu", res%.int a[ 10] = {1,5,3,8,4,2,6,9,7}; int *p; p = &a[2]; p[0] = 10; p[1] = 15; What are the values of a? Select one: O a. {10,15,3,8,4,2,6,9,7} O b. {1,15,10,8,4,2,6,9,7} O c. {1,5,10,15,4,2,6,9,7} O d. {1,10,15,8,4,2,6,9,7}#include <stdio.h>#include <string.h> int findRepeat(char* s){int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++){for (j = i + 1; j < strlen(s); j++){if (s[i] == s[j]){p = i;break;}}if (p != -1)break;}return p;} int main(){char str[] = "Hello World";int pos = findRepeat(str);if (pos == -1)printf("Not found");elseprintf("%c", str[pos]);return 0;}can you please explain this code for me