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- State whether true or false. The following code will throw an error: double a = 2; double b = 3; int c = a * b;22. What is the value of x after the following statements are executed? int x = 5; switch(x) { case 5: x += 2; case 6: x++; break; default: x *= 2; break; }X ، معلومات الدخول الى د Quiz: FinalExam quizzes/4585/take/questions/74430 Question 9 2 pts What is the output of the following code? (NOTE: There are no spaces between the output) void test () { static int x = 0; int y = 1; X = X + 2; y =y + 13; cout<Evaluate the following expressions, assume the following declarations: int x = 4 /3 * 2; int y = 9/ 2; int num = 6; num *= x + y; What is the value of the num after expression is evaluated?5- What is the output for y? int y = 0; for (int i = 0; i< 10; ++i) { y +=i; } cout << y;After the following code is executed, what is the value of i? int i;int *p;p = &i;i = 1;*p = 2;Convert the following statements into intermediate code: int r=0;for (int i=0; i<10; i++) r=r+i;Analyze the following code: int x = 0;if (x > 0) ;{System.out.println(x);} The code has syntax error. The code has run time error. The value of variable x is always printed because the print statement is not controlled by the if condition. Nothing is printed because x > 0 is false if x = 0.Given the following declaration: int x; int* p; Which of the following expressions is allowed? Select one: a. p = x; b. p = &x; %3D C. p = *x; d. x = p;The correct statements are: For L = 0, L* = {e} For L = {e}, L* = {e} OL+ = LL* L* = LL+Find the error in the following code and explain how to fix it: #include int main(void) { int *ptr; int m 1003; ptr = m; printf("%d",*ptr); } %3D4) write down whether the following statements is valid or not valid int i=11, m=51; int *pl, *p2, *p3; a- p3 = p2 - pl; b- p3 = p2 - m*i; c- m=p%3; d- pl = pl/m;SEE MORE QUESTIONS