What is the maximum index of the array: int[] intArray = { 1, 2, 3, 5, 6, 7 }; Select one: O a. None of the choices O b. 4 Ос. 5 O d. 7 О е. 6 What is the index number of the last element of an array with 30 elements? Select one: Оа. 31 O b. 30 C. 29 O d. None of these О е. 0
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- def sum_threshold_2d_array(array, threshold):"""Iterate through each element of the 2d array using nested loops.Sum up the values that are greater than a threshold value given as an input parameter.:param array: a 2d array:param threshold: a threshold value (valid int or float):return: sum total of values above the threshold"""passGiven the array: array, 5> A1 = { 18, 4, 5, 6, 67, 22, 44, 89, 14, 7, 33, 49, 12, 5, 110 }; What is element A1[5][3] O 89 O 49 0 5 0 7 UndefinedCreate an array of 15 integers. Add all elements located at ODD index positions and sum also all numbers located at EVEN(Assume zero index is even) index positions in the linear array. The user will be the one to input each item in the array of 15 elements. Display also the inputted integers in the array. Given the sample layout w/ test data below:
- Review the code snippet. if numbersomeArray. Index { print (someArray[number]) print("Array index is out of range") else { What array property is used to return the size of the array? Complete the code by entering the property in the box.In [ ]: We obtained an array with N = 10 values, scattered about mean of 25 (mm). Let's calculate the mean, standard deviation, standard deviation of the mean and 20-uncertainty SL of these numbers. In the following code, do these steps: • In the first cell, add a brief comment that explains what each statement does. Start each comment with a # sign. • In the second cell, delete the raise Not ImplementedError() code line and print the standard deviation and 20-uncertainty on the screen (follow the example for mean_L) mean_L = np.mean (L) print("Mean length: ", mean_L) stddev_L = np. std (L, ddof=1) stddev_mean_L = stddev_L/np.sqrt(N) uncertainty_L = 2*stddev_mean_L In [ ] V #YOUR CODE HERE raise NotImplementedError() #calculates the mean of L In the above code, the green expressions on the right hand side, such as np.mean, np. std and np.sqrt are functions built into the numpy package of Python. The names on the left hand side are variable names invented by me.Consider the array definitionint num [10] = {3, 3, 3};Pick the Correct answers A. num [9] is the last element of the array num B. The value of num [ 8] is 3 C. The value of num [ 3 ] is 3 D. None of the above
- A three-dimensional array called watermelon is declared as based on the row-wise manner as below: int watermelon [3][2][2]= {9, 7, 1, 5, 9, 7, 1, 5, 9, 7 ,1, 5}; Rewrite the sequence of watermelon array if it is accessed in column wise manner. Select one: A.9 9 9 7 7 7 1 1 1 5 5 5 B.9 7 1 5 9 9 7 7 1 1 5 5 C.5 1 7 9 5 1 7 9 5 1 7 9 D.9 7 1 5 9 7 1 5 9 7 1 5TODO 1: To construct an array of 120 values between -4 and 4, use the NumPy method np.linspace() (docs). To do so, pass the parameters -4, 4, and 120. Put the results in the variable x_values. mu = 0 # mean sig = 1 # std # TODO 1 x_values = display(x_values) todo_check([ (x_values.shape == (120,),'x_values does not have the correct shape of (120,)'), (np.all(np.isclose(x_values, np.array([-4.…Please assist with Java coding (Netbeans) Create a two-dimensional array to contain the three different MCSD Marks (JD521, PRG521, and IP521) for six different students. A single array must be used to store the student names (Maxwell, Carl, Gerhard, Paul, James, and Cena).Allow a user to enter in a number, ranging from 1 to 6, which will represent the student position in the table MCSD max. The program can only stop when the user enter a number greater than 6.Printout the student name including the JD521, PRG521, and IP521 max, the total of marks and the average of all marks. Use a condition statement to decide that the student has passed or not (Pass rate is 70).
- An array called number contains 20 integer values and must be filled with values in the following way: Fill the array with consecutive even numbers starting from 10. Start again at the first element and increase every fourth element with 3. Replace the value of the first four elements each with its square. Deduct 2 from the last 3 elements. Swap the value of element 5 and element 15. Add the value of the first element to that of the last element Add consecutive integers (starting from 1) to all even elements.Remember, the first element has a subscript of 0 and the last element (element 20) has a subscript of 19.The following must be displayed: All elements must be displayed each on a new line. Identify each element clearly. Display the highest value in the array. The lowest value in the array must be displayed. Count and display how many even values and how many odd values the array contains.1. Create a 2D char array called grades, to save the grades for three students for five courses (size 3 by 5). Write the nested for loop to initialize the first row with ‘A’, second row ‘B’, and third-row ‘C’. 2. Say the second student got C for the fifth course. The third student got an A for the first course. Make the changes to the above array. 3. Print out the array elements in the 2-dimensional format like the following. Make sure you print out the student # and course numbers so one can easily locate an array element. Format your output like the following.1. Create a 2D char array called grades, to save the grades for three students for five courses (size 3 by 5). Write the nested for loop to initialize the first row with ‘A’, second row ‘B’, and third-row ‘C’. 2. Say the second student got C for the fifth course. The third student got an A for the first course. Make the changes to the above array. 3. Print out the array elements in the 2-dimensional format like the following. Make sure you print out the student # and course numbers so one can easily locate an array element. Format your output like the following. After initialization: Grades of 3 students Course1 Course2 Course3 Course4 Course5Student 1: A A A A AStudent 2: B B B B BStudent 3: C C C C C After change:…