What is the enthalpy change when 8.20 moles ammonium chloride form in the following equation? N2 (g) + 4 H2 (g) + Cl2 (g)   -->   2 NH4Cl (s)     Delta H = – 628.8 kJ a. – 2.58 x 103 kJ b. – 1.29 x 103 kJ c. + 314.4 kJ d. – 314.4 kJ e. – 628.8 kJ f. – 5.16 x 103 kJ g. none of these d. – 314.4 kJ

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
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What is the enthalpy change when 8.20 moles ammonium chloride form in the following equation?

N2 (g) + 4 H2 (g) + Cl2 (g)   -->   2 NH4Cl (s)    

Delta H = – 628.8 kJ

a. – 2.58 x 103 kJ
b. – 1.29 x 103 kJ
c. + 314.4 kJ
d. – 314.4 kJ
e. – 628.8 kJ
f. – 5.16 x 103 kJ
g. none of these
d. – 314.4 kJ

 

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