What is the chi-square value of the pumpkin population? round up and use four decimal points After doing some crosses and genotyping some individuals, you determined that the number of individuals homozygous dominant for the largest pumpkin allele is 98, 80 are heterozygous for medium size, and 20 are homozygous recessive for small size.
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- Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?Using the HardyWeinberg Law in Human Genetics In a given population, the frequencies of the four phenotypic classes of the ABO blood groups are found to be A = 0.33, B = 0.33, AB = 0.18, and i = 0.16. What is the frequency of the i allele?A population of dragons is as follows: 46 are green with genotype GG 106 are green with genotype Gg 56 are red with genotype gg Is this population in Hardy-Weinberg equilibrium? Assume 1 degree of freedom for your chi-square test.
- Give the genotype of the parents and determine the linkage map of the three genes bm (brown midrib), v (virescent seedling), and pr (purple aleurone) in maize from the results of the cross below. Genotypes of offspring Total and Frequency percentage V bm 230 467 pr + 237 42.1% + + bm 82 161 pr V 79 14.5% V 200 395 pr bm 195 35.6% pr bm 44 86 V + 42 7.8% +This Punnett square shows allele combinations for all possible genetic crosses in the wildflower population described in Part A. CR E p= 0.7 CW q= 0.3 p= 0.7 ? CW CR CR CR CW q= 0.3 ? ? CR CW CW CW ? What are the expected genotype frequencies in the offspring generation? O 0.49 CRCR (red flowers), 0.42 CRCW (pink flowers), 0.09 CWCW (white flowers) 0.49 CRCR (red flowers), 0.21 CRCW (pink flowers), 0.30 CWCW (white flowers) O 0.09 CRCR (red flowers), 0.21 CRCW (pink flowers), 0.42 CWCW (white flowers) 0.09 CRCR (red flowers), 0.42 CRCW (pink flowers), 0.09 CWCW (white flowers)Crossing true-breeding pea plants with yellow peas with true-breeding plants with green peas yielded an F1 generation with 100% offspring plants with yellow peas. The F1 plants are self-fertilized and produce F2. In a randomly selected set of 100 peas from F2 you notice the following phenotypic numbers: 84 yellow and 16 green. Using the Hardy-Weinberg principle: What is the observed frequency of the recessive allele in this F2 population? 0.36 0.50 0.40 0.16 0.60
- APOE Allelic frequency Control EOAD LOAD Vascular disease e4 0.07 0.28 0.35 0.12 e3 0.88 0.70 0.63 0.87 What group is used as a control here? Based on this data, do you think APOE e4 allele increases one’s chance to develop EOAD or LOAD? Defend your answer. Your answer has to refer to the specific data in the table. Suppose that you want to improve this case control study by controlling one more variable that is a known risk factor for Alzheimer’s disease, how will you design your groups? Specify the risk factor you want to control and how you plan to control it.For the purpose of the assignment, we will refer to XY individuals as male and XX individuals as female. In humans, colorblindness (b) is an example of an X-linked recessive trait. In this problem, a male with colorblindness XbY marries a female who is not colorblind but is a carrier of the colorblindness allele (XXb). Using a Punnett square, determine the genotypic and phenotypic probabilities (as percentages) for their potential offspring. Give the percentages in numbers, without the percent sign, for each genotype and phenotype. Genotypes XX Xxb xbxb XY xby Phenotypes Consider females (XX) individuals only. In the two questions below, I am asking for the % of females, not % of all people. What is the % of females who are not colorblind? What is the% of females who are colorblind? Now consider makes (XX) individuals only. In the two questions below, I am asking for the % ofI'm confused about how I would figure out these two questions as I don't really understand the difference or where to start. What would genotypic frequencies be for Wildrose at pt-8 if it were in equilibrium? and How many individuals (to 2 decimal places) of each genotype would there be from Wildrose at pt-8 if it were in equilibrium?
- (1 point) Humans with the genotypes DD and Dd show the Rh+ blood phenotype, whereas those with the genotype dd show the Rh- blood phenotype. In a sample of 400 Basques from Spain, 230 people were Rh+ and 170 people were Rh-. Assuming that this population is in Hardy-Weinberg proportions, what is the allele frequency of the allele D? (a) (a) 0.348 (answer) (b) (b) 0.652 (c) (c) 0.425 (d) (d) 0.575 (e) (e) 0.288 2. (2 points) In the Basque population mentioned above, what proportion of the Rh+ individuals would be expected to be heterozygote? (a) (a) 0.454 (b) (b) 0.789 (answer) (c) (c) 0.516 (d) (d) 0.250 (e) (e) 0.500 How is the answer for #2, b? please explainI need help calculating observed allelic frequencies. I'm in a biology lab and we did a classroom experiment where we were each given genotypes and simulated multiple generations by coinflip. This is the end data after multiple generations and we need to extrapolate p & q: AA individuals - 2 Aa individuals - 13 aa individuals - 5 My understanding is that the genotypic frequencies would simply be their %. So AA would be 0.1, Aa would be 0.65, and aa would be 0.25. This should mean that AA = 0.1 = p^2 and aa = 0.25 = q^2. Which should also mean that taking the square root of these numbers would give me p and q.... but they don't add up to 1. Squaring them gives me a p value of ~0.32 and a q value of 0.5. How is this possible? Shouldn't this method work to give me p and q since I know the exact genotypic frequencies? If anyone can clear up why this doesn't work, I would be extremely appreciative. Thank you!A wild-type fruit fly (heterozygous for gray body color andred eyes) is mated with a black fruit fly with purple eyes. Theoffspring are wild-type, 721; black purple, 751; gray purple, 49;black red, 45. What is the recombination frequency betweenthese genes for body color and eye color? Using informationfrom problem 3, what fruit flies (genotypes and phenotypes)would you mate to determine the order of the body color, wingsize, and eye color genes on the chromosome?