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- the adjoining figure. This lamp can withstand a maximum voltage 3.0 v 0.4 9. Volt-ampere (V-I) charaeteristics of an incandescent lamp 16thd in and a maximum current 0.4 A. An infinite ladder network consisting a large number of these lamps is also shown in the figure given belo How much maximum voltage can be applied between the terminals A and B, so that no lamp gets damaged? (Use V5 = 2.2). Ans:x4.2V Hint: Curentin all bulls except first isGiven the circuit below and that R1=1.7ohm,R2=3.5ohm,Emf1=2.1V and Emf2=6.3V. What is the current through the section ac?150 100 + VA- a -4V AVA -7V 81. B b Figure 2 shows a simplified model of a gas-discharge lamp. One characteristic of these lamps is that they exhibit negative resistance; in other words, as current increases the voltage drops further, making such lamps inherently unstable. As such, a current-limiting ballast is required. For the connection shown in the figure: 1. Find the equivalent Thevenin circuit of the lamp. 2. Find the ballast resistance needed to limit the current drawn from a 24-volt source to 6 amperes.What is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagramWhich of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increasesRepresent a circuit diagram that applies an alternating voltage of 250 V over a 5-0 having access to an alternating voltage source 220 V with a series resistance of 10 Q, a transformer core with a winding of 1600 turns with 0.02 0/spiral, the which a derivation can be made at any point and resistance wires despicable.12 - L.-p- -- yuc-. For the circuit shown in figure, what current (in A) does the ammeter read if e=10.8 V (ideal battery), R:=2.0 0, R2=6.0 0, and R3=8.0 0? (A Option1 Option2 Option3 Option4 Option5 R2 0.45 0.85 1.15 1.65 2.05 RUse Kirchhoff's Law to solve for the current passing through each resistor. Compare it with what you got from the PHET Simulation A D 392 www 6V E www F 192 www 292 352 www 9V B CConsider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-Which one or ones of the following statements about Kirchhoff's rules are correct? I) The junction rule is based on the law of conservation of energy. II) The loop rule is based on the law of conservation of energy. III) The number of required equations to find the unknown currents has to be as many as the number of all possible loops. O A) Il and II B) II O C) I and II O D) II O E) Ishfdjkfdrhnacoioeniodinopidopdnieocmixoxwmipdf.ziudSALIDUDetu The equivalent resistance of three resistors A, B and C connected in parallel is 1.5 ohms. If A is thrice of B and C is 1/4 of B. Find the equivalent resistance when the three of them are connected in series? dhffrriru9eePt A 6v battey, delivrers loMA to thvee resistors in faralkl, R, =1kr,R2 =2K2,R3=Rx- Calcalate: a) Current in b) Power dissipatiod by Rx and R,-[Anss 6mw, 36mn. c) Resistance ratio Rx/R--(Ans: 6/)- d) Current ratio Ii/Ix. Anst 6/4). Rx stheatis Ix Anss 1 mÁ)SEE MORE QUESTIONS