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We want to conduct the hypothesis test Ho: Attachment pattern and child care time are independent, versus H: Attachment pattern and child care time are dependent. Recall that the test statistic X2 for the chi-square test of independence is given by the following. _Σ(0,-Ê,² ij' The observed cell counts, O., are given in row i and column j of the given contingency table. The estimated expected cell counts, Ê, can be calculated based on the data assuming that the rows and columns are independent, which is claimed by the null hypothesis. If Ho is assumed to be true, then the estimate of the expected cell count in row i and column j is given by the following. Secure X² Anxious Total 65 The total number of observations is n, r, is the total for row i, and c, is the total for column j. First determine the row and column totals, r, and c,, for the given contingency table, as well as the total of all observations, n. Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) = rcj n 23 9 C₁ = 23 +9 C₂ = 34 8 4 6 Total ₁23 +34 + 4 = 2 = n = ₁ + ₂ = C₁ + ₂ + C3

We want to conduct the hypothesis test Ho: Attachment pattern and child care time are independent, versus H: Attachment pattern and child care time are dependent. Recall that the test statistic X2 for the chi-square test of independence is given by the following. _Σ(0,-Ê,² ij' The observed cell counts, O., are given in row i and column j of the given contingency table. The estimated expected cell counts, Ê, can be calculated based on the data assuming that the rows and columns are independent, which is claimed by the null hypothesis. If Ho is assumed to be true, then the estimate of the expected cell count in row i and column j is given by the following. Secure X² Anxious Total 65 The total number of observations is n, r, is the total for row i, and c, is the total for column j. First determine the row and column totals, r, and c,, for the given contingency table, as well as the total of all observations, n. Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) = rcj n 23 9 C₁ = 23 +9 C₂ = 34 8 4 6 Total ₁23 +34 + 4 = 2 = n = ₁ + ₂ = C₁ + ₂ + C3

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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We want to conduct the hypothesis test Ho: Attachment pattern and child care time are independent, versus H: Attachment pattern and child care time are dependent. Recall that the test statistic X2 for the chi-square test of independence is given by the following. The observed cell counts, O, are given in row i and column j of the given contingency table. The estimated expected cell counts, can be calculated based on the data assuming that the rows and columns are independent, which is claimed by the null hypothesis. If Ho is assumed to be true, then the estimate of the expected cell count in row i and column j is given by the following. Secure x² - Σ(0,-8,3² = The total number of observations is n, r, is the total for row i, and c, is the total for column j. First determine the row and column totals, r, and c,, for the given contingency table, as well as the total of all observations, n. Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) Anxious Total rcj n 23 9 C₁ = 23 +9 C₂ 34 8 C3= 4 6 Total r₁23 +34 + 4 = r2 = n = ₁ + ₂ = C₁ + ₂ + 3
Transcribed Image Text:We want to conduct the hypothesis test Ho: Attachment pattern and child care time are independent, versus H: Attachment pattern and child care time are dependent. Recall that the test statistic X2 for the chi-square test of independence is given by the following. The observed cell counts, O, are given in row i and column j of the given contingency table. The estimated expected cell counts, can be calculated based on the data assuming that the rows and columns are independent, which is claimed by the null hypothesis. If Ho is assumed to be true, then the estimate of the expected cell count in row i and column j is given by the following. Secure x² - Σ(0,-8,3² = The total number of observations is n, r, is the total for row i, and c, is the total for column j. First determine the row and column totals, r, and c,, for the given contingency table, as well as the total of all observations, n. Low (0-3 hours) Moderate (4-19 hours) High (20-54 hours) Anxious Total rcj n 23 9 C₁ = 23 +9 C₂ 34 8 C3= 4 6 Total r₁23 +34 + 4 = r2 = n = ₁ + ₂ = C₁ + ₂ + 3
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