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We derived in class that, for the dipole radiation, the vector potential at distance from the radiator is A Helleikr (a) Instead of obtaining B from E, as stated in class notes, show that, keeping only the term involving 1/r, B=VXA = kuolleikr fx 2. 4π (b) Verify that this answer is the same as the one obtained using B = -x E, with E = iwuolleikr 4π sin obtained in class. 2 6

We derived in class that, for the dipole radiation, the vector potential at distance from the radiator is A Helleikr (a) Instead of obtaining B from E, as stated in class notes, show that, keeping only the term involving 1/r, B=VXA = kuolleikr fx 2. 4π (b) Verify that this answer is the same as the one obtained using B = -x E, with E = iwuolleikr 4π sin obtained in class. 2 6

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Question

3. We derived in class that, for the dipole radiation, the vector potential at distance r from the
Holl eikr
-2.
radiator is A =
4πT
до
(a) Instead of obtaining B from E, as stated in class notes, show that, keeping only the term
involving 1/r, B = VXA =
ikuolleikr
-fx 2.
4π
ין
(b) Verify that this answer is the same as the one obtained using B = --V × E, with
iwμoll eikr
E=
4π
"
-sin e obtained in class.
(N
A
r

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