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- Python Programming Problem: Simple Soccer Point TableThe programmer will design a simple point table lookup and update application. The table contains some basic information: team_name, match_played, win, draw, loss, point and rank. Design Solution:1. English Premier League is a prestigious soccer league. Here is the result of its one session. Man. City|38|32|2|4|98|1Liverpool|38|30|7|1|97|2Chelsea|38|21|9|8|72|3Tottenham|38|23|2|13|71|4Arsenal|38|21|7|10|70|5 2. Hypothetically, you have been assigned to design a simple lookup software for prestigious ‘English Premier League’ from a given point table. The point table contains team_name, match_played,win, draw, loss, points and rank. 3. The input file, ‘previous_result.txt’ has been provided to you above the top 5 teams in 2018-19 session. Your software needs to be able to search and update the point table based on user input. For example: The first time Chelsea played 38, the second time it changed (based on user input) to 40 and so…Dijkstra's algorithm Weight Class Implementationlanguage : C++ Note : Skelton Files Provided Please check the linksproject Details:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/ Files:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/src/ Please provide clear and complete solution for thumps up.Please DO NOT respond to this question by copy/pasting the code provided elsewhere on the site, none of those work. Thanks. Virtual Memory Lab This lab project addresses the implementation of page-replacement algorithms in a demand-paging system. Each process in a demand-paging system has a page table that contains a list of entries. For each logical page of the process, there is an entry in the table that indicates if the page is in memory. If the page is in memory, the memory frame number that page is resident in is indicated. Also, for each page, the time at which the page has arrived in memory, the time at which it has been last referenced, and the number of times the page has been referenced since the page arrived in memory are maintained. The page table data structure is a simple array of page-table entries (PTEs). Each PTE contains five fields as defined below: struct PTE { int is_valid; int frame_number; int arrival_timestamp; int…
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- Write, test, and debug (if necessary) PHP scripts for the specifications that follow write functions and the code to test them. Parameter: A string containing words that are delimited on the left with spaces and on the right with spaces, commas, periods, or question marks. Return value: The three most common words in the string that have more than three letters Parameter: An array of strings. Return value: A list of the three strings that occur most frequently in the parameter arrayDeliverable #2: How many operations in nested for loops? Implement the following psuedocode as the function two_dimensional_loop (n) in the cell below: count = 0 for i = 0 to n-1 : for j = i to n-1 : count = count + 1 return count ► def two_dimensional_loop(n) : # complete to satisfy the instructions and implement the pseudocode || return 0 expectEqual (two_dimensional_loop (520),135460) expectEqual (two_dimensional_loop (1234), int(1234* (1234+1)/2)) 个 ↓please use c# i just want you to modify the code please Download the solution and run it locally. Familiarize yourself with the code, then modify it as follows: 1. Replace the use of depth first search with the breadth first search algorithm. 2. Add at least 5 more employees // The code below was mostly taken directly from:// https://www.csharpstar.com/csharp-depth-first-seach-using-list/using System;using System.Collections.Generic;using System.Linq;using System.Text;using System.Threading.Tasks; namespace depthFirstSearch{ class Program { public class Employee { public Employee(string name) { this.name = name; } public string name { get; set; } public List<Employee> Employees { get { return EmployeesList; } } public void isEmployeeOf(Employee e) {…
- Find logic errors: #include <Adafruit_NeoPixel.h>#include <string.h> #define NEOS 8#define NPX 10#define AVGS 100 int runsamps[AVGS];double curavg;int count; Adafruit_NeoPixel pixels(NPX, NEOS, NEO_GRB+NEO_KHZ800); void setup() {// put your setup code here, to run once:pixels.begin();memset(runsamps, 0, AVGS*sizeof(int));count = 0;curavg = 50;} void loop() {// put your main code here, to run repeatedly:int newdata;int scaleavg;pixels.clear();newdata = analogRead(8);curavg += (double)runsamps[count]/AVGS;runsamps[count] = newdata;curavg -= (double)newdata/AVGS;scaleavg = round(map(curavg, 0, 1023, 0, 10));for (int n = 0; n < scaleavg; n++){pixels.setPixelColor(n, pixels.Color(82, 35, 152));pixels.show();}delay(10);count++;}Create Java Book objects using the following data and place them in a List. (Fields: Author, Title, Year, Price) Java Programming,Deitel,2016,68.75Python Programming,Gaddis,2018,78.56Data Analytics,Norman,2017,89.56Block Chain Development,Wilson,2019,87.45Web Development,Brown,2018,98.98 Create TWO List Comparators to sort the Book objects in ascending order: One by Book Title and the second by Book Year. Using each Comparator, SORT the List once by Title and again by Year. NOTE: You MUST use the Comparator to SORT. Cannot use any other built in sort methods. Output each SORTED List on Console in a format same as the data shown above (One Book per line, comma separated).SKELETON CODE IS PROVIDED ALONG WITH C AND H FILES. #include <stdio.h> #include <stdlib.h> #include <string.h> #include <stdbool.h> #include "node.h" #include "stack_functions.h" #define NUM_VERTICES 10 /** This function takes a pointer to the adjacency matrix of a Graph and the size of this matrix as arguments and prints the matrix */ void print_graph(int * graph, int size); /** This function takes a pointer to the adjacency matrix of a Graph, the size of this matrix, the source and dest node numbers along with the weight or cost of the edge and fills the adjacency matrix accordingly. */ void add_edge(int * graph, int size, int src, int dst, int cost); /** This function takes a pointer to the adjacency matrix of a graph, the size of this matrix, source and destination vertex numbers as inputs and prints out the path from the source vertex to the destination vertex. It also prints the total cost of this…