Used 24.38 mL of a 0.1014M NaOH solution to titrate the dilute HCL solution to the endpoint in one trial. The concentration of the dilute HCl solution = 0.09889M and the concentration of the stock HCl=0.9889M. Then was pipetted 25.00 mL of the stock HCl and added antacid tablet and determined the concentration of the antacid-HCl = 0.6279 M. What was the ANC of the antacid tablet (moles of H+ neutralized per tablet)?
Used 24.38 mL of a 0.1014M NaOH solution to titrate the dilute HCL solution to the endpoint in one trial. The concentration of the dilute HCl solution = 0.09889M and the concentration of the stock HCl=0.9889M. Then was pipetted 25.00 mL of the stock HCl and added antacid tablet and determined the concentration of the antacid-HCl = 0.6279 M. What was the ANC of the antacid tablet (moles of H+ neutralized per tablet)?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.102QE
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Used 24.38 mL of a 0.1014M NaOH solution to titrate the dilute HCL solution to the endpoint in one trial. The concentration of the dilute HCl solution = 0.09889M and the concentration of the stock HCl=0.9889M. Then was pipetted 25.00 mL of the stock HCl and added antacid tablet and determined the concentration of the antacid-HCl = 0.6279 M. What was the ANC of the antacid tablet (moles of H+ neutralized per tablet)?
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