Use the logarithmic Arrhenius equation and the following data showing the dependence of temperature and reaction rate constant k to predict the activation energy barrier (E₂) for the reaction shown. Hint: try graphing In(k) against 1/T from the data in the table and estimate the intercept, which is In(A), and the slope, which is Ea/R. In case you get stuck, you can use the Arrhenius factor for this reaction (A = 8.1 x 10⁹ mol-¹Ls-¹) and substitute it into the equation. 2NO2 (g) T(K) 673 683 693 703 713 O E = 1.2 x 105 kJmol-1 O E₂8.314 JK ¹mol-1 O E₂ -119601 Jmol-¹ O E₂ = 7.7 x 106 J O E₂ 1.2 x 10² kJmol-1 = 2NO (9) k (mol ¹Ls ¹) 7.8 10 14 18 24 + O2 (g)

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter11: Chemical Kinetics: Rates Of Reactions
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Use the logarithmic Arrhenius equation and the following data showing the dependence of
temperature and reaction rate constant k to predict the activation energy barrier (E₂) for the reaction
shown. Hint: try graphing In(k) against 1/T from the data in the table and estimate the intercept, which
is In(A), and the slope, which is E₂/R. In case you get stuck, you can use the Arrhenius factor for this
reaction (A = 8.1 x 10⁹ mol-¹Ls ¹) and substitute it into the equation.
2NO(g)
+ O2 (g)
2NO2 (9)
T(K)
673
683
693
703
713
O Ea 1.2 x 105 kJmol-1
O E₂8.314 JK ¹mol-1
O E₂ -119601 Jmol-¹
O E₂
7.7 x 106 J
1.2 x 10² kJmol-¹
O Ea
O E₂ = 0.12 kJ
k (mol ¹Ls ¹)
7.8
10
14
18
24
Transcribed Image Text:Use the logarithmic Arrhenius equation and the following data showing the dependence of temperature and reaction rate constant k to predict the activation energy barrier (E₂) for the reaction shown. Hint: try graphing In(k) against 1/T from the data in the table and estimate the intercept, which is In(A), and the slope, which is E₂/R. In case you get stuck, you can use the Arrhenius factor for this reaction (A = 8.1 x 10⁹ mol-¹Ls ¹) and substitute it into the equation. 2NO(g) + O2 (g) 2NO2 (9) T(K) 673 683 693 703 713 O Ea 1.2 x 105 kJmol-1 O E₂8.314 JK ¹mol-1 O E₂ -119601 Jmol-¹ O E₂ 7.7 x 106 J 1.2 x 10² kJmol-¹ O Ea O E₂ = 0.12 kJ k (mol ¹Ls ¹) 7.8 10 14 18 24
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