Use the Intermediate Value Theorem to show that the given function has a zero in the interval [0, 3]. f(x) = x² + 5x - 3 f (x) Click for List f(0) = Number f(3) = Number on the interval [0, 3]. By the Intermediate Value Theorem, there is a value c in [0,3] such that f (c) = 0, since f (0) Click for List 0 and f (3) Click for List 0. Y

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Polynomial Functions
Section3.2: Polynomial Functions Of Higher Degree
Problem 6ECP
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Use the Intermediate Value Theorem to show that the given function has a zero in the interval [0,3].
f(x) = x²
=£
+523
f (x) Click for List
f(0) = Number
f(3) = Number
on the interval [0, 3].
By the Intermediate Value Theorem, there is a value c in [0, 3] such that f(c) = 0, since
f (0) Click for List
0 and f(3)
Click for List
0.
Y
Submit A
Transcribed Image Text:Use the Intermediate Value Theorem to show that the given function has a zero in the interval [0,3]. f(x) = x² =£ +523 f (x) Click for List f(0) = Number f(3) = Number on the interval [0, 3]. By the Intermediate Value Theorem, there is a value c in [0, 3] such that f(c) = 0, since f (0) Click for List 0 and f(3) Click for List 0. Y Submit A
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