Use the following information According to a recent survey, high school students average 100 text messages daily. Assume the population standard deviation is 21 text messages a day. Suppose you take a random sample of 49 high school students. P=106 σ=21 n= 49 Std=3 50. K Std 47. What is the probability that the mean of this sample is less than 105? 48 49. C. d. a. b. d. 0.0475 0.9525 C. 0.4525 d. 0.5910 a. b What is the probability that the mean of this sample is between 90 and 105? 0.4996 0.4525 0.9521 0.0479 a. b. a b. d. Incomes in a certain town are normally distributed with a mean of $36,000 and standard deviation $7000. A random sample of 75 households is taken. What is the standard error of the sample mean? $808.31 $93.33 $7000 $6000 The owner of a Dickson St. bar would like to determine whether or not the mean age of the bar's customers is over 24. If so, she plans to alter the nightly drink specials to cater to this older audience. If she concludes that the mean age is over 24 when it is not, she error. If she concludes that the mean age is not over 24 when it is, sh makes a makes a error. Type II; Type II Type I; Type I Type I; Type II Type II; Type I

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 53E
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Use the following information for the next 2 questions.
According to a recent survey, high school students average 100 text messages daily. Assume the
population standard deviation is 21 text messages a day. Suppose you take a random sample of
49 high school students.
P=106
σ=21 n = 49
Std=3
50.
R
Std
47. What is the probability that the mean of this sample is less than 105?
0.0475
48.
49.
a.
b
C.
d.
C
d.
d.
What is the probability that the mean of this sample is between 90 and 105?
0.4996
0.4525
0.9521
0.0479
a.
b.
d.
0.9525
0.4525
0.5910
Incomes in a certain town are normally distributed with a mean of $36,000 and standard
deviation $7000. A random sample of 75 households is taken. What is the standard error
of the sample mean?
a
$808.31
b.
makes a
makes a
The owner of a Dickson St. bar would like to determine whether or not the mean age of
the bar's customers is over 24. If so, she plans to alter the nightly drink specials to cater
to this older audience. If she concludes that the mean age is over 24 when it is not, she
error. If she concludes that the mean age is not over 24 when it is, she
$93.33
$7000
$6000
error.
a.
Type II; Type II
b. Type I, Type I
Type I; Type II
Type II; Type I
Transcribed Image Text:Use the following information for the next 2 questions. According to a recent survey, high school students average 100 text messages daily. Assume the population standard deviation is 21 text messages a day. Suppose you take a random sample of 49 high school students. P=106 σ=21 n = 49 Std=3 50. R Std 47. What is the probability that the mean of this sample is less than 105? 0.0475 48. 49. a. b C. d. C d. d. What is the probability that the mean of this sample is between 90 and 105? 0.4996 0.4525 0.9521 0.0479 a. b. d. 0.9525 0.4525 0.5910 Incomes in a certain town are normally distributed with a mean of $36,000 and standard deviation $7000. A random sample of 75 households is taken. What is the standard error of the sample mean? a $808.31 b. makes a makes a The owner of a Dickson St. bar would like to determine whether or not the mean age of the bar's customers is over 24. If so, she plans to alter the nightly drink specials to cater to this older audience. If she concludes that the mean age is over 24 when it is not, she error. If she concludes that the mean age is not over 24 when it is, she $93.33 $7000 $6000 error. a. Type II; Type II b. Type I, Type I Type I; Type II Type II; Type I
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