Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Hg2+ (aq) + 21 (aq) → Hg(s) + 1₂ (s) red Hg²+ (aq) + 2e¯ → Hg(s) Eº I₂ (s) + 2e¯ → 21¯ (aq) = AG° || K for this reaction would be KJ Eº red = = 0.855 V 0.535 V - than one.

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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 150CP: Given the following two standard reduction potentials, solve for the standard reduction potential of...
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Use standard reduction potentials to calculate the
standard free energy change in kJ for the reaction:
Hg2+ (aq) + 21- (aq) → Hg(s) + I₂ (s)
2+
Hg²+ (aq) + 2e¯ → Hg(s) Eº = 0.855 V
red
0.535 V
I2 (s) + 2e → 21¯ (aq)
=
-
AGO
||
K for this reaction would be
kJ
Eº
red
-
than one.
Transcribed Image Text:Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Hg2+ (aq) + 21- (aq) → Hg(s) + I₂ (s) 2+ Hg²+ (aq) + 2e¯ → Hg(s) Eº = 0.855 V red 0.535 V I2 (s) + 2e → 21¯ (aq) = - AGO || K for this reaction would be kJ Eº red - than one.
Use standard reduction potentials to calculate the
standard free energy change in kJ for the reaction:
2Cu²+ (aq) + Hg(1) → 2Cu† (aq) + Hg²+ (aq)
Cu²+
(aq) + e¯ → Cu+ (aq) Eº = 0.153 V
red
Hg²+ (aq) + 2e¯ →
E red
AGO
K for this reaction would be
kJ
Hg(1)
Hg(1)
= 0.855 V
-
than one.
Transcribed Image Text:Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2Cu²+ (aq) + Hg(1) → 2Cu† (aq) + Hg²+ (aq) Cu²+ (aq) + e¯ → Cu+ (aq) Eº = 0.153 V red Hg²+ (aq) + 2e¯ → E red AGO K for this reaction would be kJ Hg(1) Hg(1) = 0.855 V - than one.
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