use python Implement a recursive algorithm which will print all the elements of a non-dummy headed singly linked linear list in reversed order. Example: if the linked list contains 10, 20, 30 and 40, the method will print 40 30 20 10 Note: you’ll need a Singly Node class for this code.
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use python
Implement a recursive
Example: if the linked list contains 10, 20, 30 and 40, the method will print
40
30
20
10
Note: you’ll need a Singly Node class for this code.
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- A consecutive sequence a list of numbers that are organized in increasing order with the next eleme. one bigger than the current. Write a non-recursive method "lengthConsec", which takes an IntNode myList as the parameter and returns the length of the consecutive sequence in myList. To simplify the implementation, you can assume that there is no more than one consecutive sequence in the list. For example, in the following linked list, the consecutive sequence begins at node "5" and ends at node "7", so lengthConsec (myList) should return 3 in this case. myList 8 13 4 public class IntNode { 12 private int m_data; private IntNode m_link; Consecutive sequence 6 7 28Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…
- What the code is about: Implement a recursive algorithm to add all the elements of a non-dummy headed singly linked linear list. Only head of the list will be given as parameter where you may assume every node can contain only integer as its element.Note: you’ll need a Singly Node class for this code. **PLEASE EXPLAIN HOW THE NODE CLASS AND THE CONSTRUCTOR OF THE NODE CLASS IS WORKING IN THIS CODE** #singlty node class for single linked listclass node: def __init__(self, value = None, next=None): self.value = value self.next = nextdef AddAll(head):#takes head of single linked list head if head==None: return 0#if reached end of the linked list return AddAll(head.next) + head.value #each node's next pointer is passed in recursive call #and value of each node is added while returning from recursive callGiven a singly linked list, reverse the list. This means you have to reverse every node. For example if there are 4 nodes, the node at position 0 will move to position 3, the node at 1 will move to position 2 and so on. You do not have to write the Node class just write what you have been asked to. You are NOT allowed to create a new list. In python languageIn the Recursive Binary Search shown below, there are two base cases: Line 10: the search is exhausted without a finding a value that matches the key Line 16: the search finds a value that matches the key 1 public class RecursiveBinarySearch { 2 public static int binarySearch(int[] list, int key) { 3 int low = 0; 4 int high = list.length - 1; 5 return binarySearch(list, key, low, high); 6 } 7 8 private static int binarySearch(int[] list, int key, 9 int low, int high) { 10 if (low > high) // The list has been exhausted without a match 11 return -low - 1; 12 13 int mid = (low + high) / 2; 14 if (key < list[mid]) 15 return binarySearch(list, key, low, mid - 1); 16 else if (key == list[mid]) 17 return mid; 18 else 19 return binarySearch(list, key, mid + 1, high); 20 } 21 22 public static void main(String[] args) { 23 int[] list = {3, 5, 7, 8, 12, 17,…
- Implement a recursive function void deleteMax() on the IntList class (provided). The function will delete from the IntList the IntNode containing the largest value. If there are multiple nodes containing this largest value, only delete the 1st one. Be careful not to cause any memory leaks or dangling pointers. You may NOT use any kind of loop (must use recursion). You may NOT use global or static variables. You may NOT use any standard library functions. Ex: list: 5->7->1->16->4->16->3 list.deleteMax(); list: 5->7->1->4->16->3 IntList.h #ifndef __INTLIST_H__#define __INTLIST_H__ #include <ostream> using namespace std; struct IntNode {int value;IntNode *next;IntNode(int value) : value(value), next(nullptr) {}}; class IntList { private:IntNode *head; public: /* Initializes an empty list.*/IntList() : head(nullptr) {} /* Inserts a data value to the front of the list.*/void push_front(int val) {if (!head) {head = new IntNode(val);} else {IntNode…In JavaScript use recursion to find the sum of all pages in the following: function getPageTotal(list) {// your code here// returns an integer}Example test case:Input: {"book":"A","pages":50,"next":{"book":"B","pages":25,"next": null}}Output: 75Reasoning: 50 + 25 pagesQ2 Write the number of point and the letter of the correct answer: 1. The number of fields in the node of double linked list as circular is.............. A. 2 B. 3 C. 4 D. 5 2. Which the following can implement by stack? A. recursive problems B. reveres words C. both a and b D. None of the above 3. The infix expression for the postfix expression: ab+c/ is: A. a+b/c B. (a+b)/c C. a+(b/c) D. None of above 4. With queue data structure, The condition last=first indicates that A. queue is empty B. queue is full C. queue has only one element D. None of the above choose the correct answer (data structure in java) 2 10 (0.5X2 Page 1 of 4
- Write a recursive method that takes as input a reference to the curhead of a linked list storing integers and returns the smallest value in the list. You may assume that list will contain at least one element. Use C#Java help, can you please explain this I'm a beginner and I'm lost:( Implement a nested class DoubleNode for building doubly-linked lists, where each node containsa reference to the item preceding it and the item following it in the list (null if there is no suchitem). Then implement methods for the following tasks:• Print the contents of the list• Insert at the beginning• Insert at the end• Remove from the beginning• Remove from the end• Insert before a give node (Insert before the first occurrence of the node, if thenode exists; else insert at the end)• Insert after a given node (Insert after the first occurrence of the node, if the nodeexists; else insert at the end)• Remove a given node (Remove the first occurrence of the node, remove nothing ifnode not found)• Move to front (move the first occurrence of the node to the front)• Move to end (moved and first occurrence of the node to the end)Write a tester program and test your implementation. You must test each of these cases…In Java: Modify the attached program code below According to the question a, b and c a. Replace the appendNode() method by an insertNode() method which inserts the new node in such a way to keep the list always sorted in increasing order. b. Add a recursive method displayReverse() which displays the list in reverse order. c. Do the needed changes to the main()in order to reflect the above two changes. public class DoublyLinkedList { private Node head;private Node tail;private int size; DoublyLinkedList() {tail = head = null;size = 0;} public void addNode(String item) {//adding a node at the endNode newNode = new Node(item);if(head == null) {head = tail = newNode;}else {newNode.prev = tail;tail.next = newNode;tail = newNode;}size++;} public boolean remove(String item) {Node current = head;boolean found = false;while((current != null)&&(!found)) {if(current.element.equals(item))found = true;elsecurrent = current.next;}if(found){if(current == head) head =…