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Following
i. interface P{
void fun(int x) ;
}
------------------------
class S implements P{
public void funny(){
System.out.print(“OOP is funny”);
}
public static void main(String args[]){
S s1 = new S();
s1.funny()
}
}
ii. public class A{
int x;
void A(int x)
{ this.x=x;
System.out.println("in Class A");
}
public static void main(String[] args){
new A(5);
}
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- Identify the error(s) in the program and describe why this error occurs. Rewrite the code after correcting all errors. package Overview interface MyInt{ int a; void seta(int alpha); } public class CheckTest implements MyInt { @Override public void seta(int alpha) {a = alpha;} public static void main(String[] args) { seta(5); } }FIX THE CODE PROVIDED BELOW Part 2 - Syntax Errors and Troubleshooting The code below has many syntax (and other) errors. Tasks:Compile the code and fix the errors one at a time. // Lab1a.java // This short class has several bugs for practice. // Authors: Carol Zander, Rob Nash, Clark Olson, you public class Lab1a { public static void main(String[] args) { compareNumbers(); calculateDist(); } publicstatic void compareNumbers() { int firstNum = 5; int secondNum; System.out.println( "Sum is: + firstNum + secondNum ); System.out.println( "Difference is: " + (firstNum - secondNum ); System.out.println( "Product is: " + firstNun * secondNum ); } public static void calculateDistance() { int velocity = 10; //miles-per-hour int time = 2, //hoursint distance = velocity * timeSystem.out.println( "Total distance is: " distanace); } } Part 3 - Print Statements and Simple Methods Use "print" and "println" statements, but use method calls to reduce the number of repeated "print"and "println"…class overload { int x; double y; void add(int a , int b) { x = a + b; } void add(double c , double d) { y = c + d; } overload() { this.x 0; %3D this.y = 0; } %3D } class Overload_methods { public static void main(String args[]) { overload obj int a = 2; double b - 3.2; obj.add(a, a); obj.add(b, b); System.out.println(obj.x + } = new overload(); + obj.y); } #3Run the code
- please help me with the following 1) make a sierpenski triangle using java and recursion. Make it similar to the code below. And please comment the code 2) Please make the follow code out put on the console. It a t square fractal import java.awt.image.*;import java.awt.Color;import java.io.*;import javax.imageio.*; public class Main{ static final int DIMENSION = 1000; static BufferedImage image = new BufferedImage(DIMENSION, DIMENSION, BufferedImage.TYPE_INT_RGB); static final int WHITE = Color.WHITE.getRGB(); static final int BLACK = Color.BLACK.getRGB(); private static void drawSquare(int x, int y, int side) { if (side <= 0) return; else { int left = x - side/2; int top = y - side/2; int right = x + side/2; int bottom = y + side/2; for (int i = left; i < right; i++) for (int j = top; j < bottom; j++) { image.setRGB(i, j, BLACK); }…class TenNums {private: int *p; public: TenNums() { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = i; } void display() { for (int i = 0; i < 10; i++) cout << p[i] << " "; }};int main() { TenNums a; a.display(); TenNums b = a; b.display(); return 0;} Continuing from Question 4, let's say I added the following overloaded operator method to the class. Which statement will invoke this method? TenNums TenNums::operator+(const TenNums& b) { TenNums o; for (int i = 0; i < 10; i++) o.p[i] = p[i] + b.p [i]; return o;} Group of answer choices TenNums a; TenNums b = a; TenNums c = a + b; TenNums c = a.add(b);1- public class Con{ public static void main(String[] args) int[] ar=(2,5,7,9}; int i=2; final int j=1; 6. for (int x:ar) 8- { 9 if(ar[i]public class TwoColors 10 { public static void main(String[] args) { Scanner in = new Scanner(System.in); 11 12 13 14 System.out.print("Enter your first favorite color: "); 15 16 // Step 2: Read in the next line of input and assign • it to a String variable color1 17 // 18 19 // Step 3: Trim spaces from both end and convert the // // 20 input to all lowercase and assign it back 21 22 to the same variable 23 24 System.out.print("Enter your second favorite color: "); 25 26 // Step 4: Read in the next line of input and assign 27 // it to a String variable color2 28 29 30 // Step 5: Trim spaces from both end and convert the // // 31 input to all lowercase and assign it back 32 33 to the same variable 34 35 // Step 6: Display a message according to the following: // 36 first color 37 second color message light blue 38 red That's wonderful! light blue 39 red That's even better! That's also great! 40 otherwise 41 42class TenNums {private: int *p; public: TenNums() { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = i; } void display() { for (int i = 0; i < 10; i++) cout << p[i] << " "; }};int main() { TenNums a; a.display(); TenNums b = a; b.display(); return 0;} Write a copy constructor for the above class TenNums. Make sure it performs deep copy. Group of answer choices TenNums(const TenNums& b) { p = b.p;} TenNums(const TenNums& b) { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = b.p[i];} TenNums(const TenNums b) { p = new int[10]; for (int i = 0; i < 10; i++) p[i] = b.p[i];} TenNums(const TenNums b) { p = b.p;}class Param3 { public int x; private void increase(int p) { x = x*p; } public void calculateX(int y) { increase(y); } public int getX() { return x; } } // in another class Param3 q3 = new Param3(); q3.x = 5; q3.calculateX(7); System.out.println(q3.getX()); what would be the answer for the last two lines ? also above were x = x*p do both x in here are the fields? wouldn't that be cnofusing?Fix all errors to make the code compile and complete. //MainValidatorA3 public class MainA3 { public static void main(String[] args) { System.out.println("Welcome to the Validation Tester application"); // Int Test System.out.println("Int Test"); ValidatorNumeric intValidator = new ValidatorNumeric("Enter an integer between -100 and 100: ", -100, 100); int num = intValidator.getIntWithinRange(); System.out.println("You entered: " + num + "\n"); // Double Test System.out.println("Double Test"); ValidatorNumeric doubleValidator = new ValidatorNumeric("Enter a double value: "); double dbl = doubleValidator.getDoubleWithinRange(); System.out.println("You entered: " + dbl + "\n"); // Required String Test System.out.println("Required String Test:"); ValidatorString stringValidator = new ValidatorString("Enter a required string: "); String requiredString =…Fix all errors to make the code compile and complete.//MainValidatorA3 public class MainA3 { public static void main(String[] args) { System.out.println("Welcome to the Validation Tester application"); // Int Test System.out.println("Int Test"); ValidatorNumeric intValidator = new ValidatorNumeric("Enter an integer between -100 and 100: ", -100, 100); int num = intValidator.getIntWithinRange(); System.out.println("You entered: " + num + "\n"); // Double Test System.out.println("Double Test"); ValidatorNumeric doubleValidator = new ValidatorNumeric("Enter a double value: "); double dbl = doubleValidator.getDoubleWithinRange(); System.out.println("You entered: " + dbl + "\n"); // Required String Test System.out.println("Required String Test:"); ValidatorString stringValidator = new ValidatorString("Enter a required string: "); String requiredString =…T/F A Java main method uses the parameter (String[ ] variable) so that a user can run the program and supply“command-line” parameters. Since the parameter is a String array, however, the user does not have to supply anyparameters.SEE MORE QUESTIONS