Under certain water conditions, the free chlorine (hypochlorous acid, HOCl) in a swimming pool decomposes according to the law of uninhibited decay. After shocking a pool, the pool boy, Geoff, tested the water and found the amount of free chlorine to be 2.6 parts per million (ppm). Twenty-four hours later, Geoff tested the water again and found the amount of free chlorine to be 2.3 ppm. What will be the reading after 2days (that is,48 hours)? When the chlorine level reaches 1.0 ppm, Geoff must shock the pool again. How long can Geoff go before he must shock the pool again? After 2 days or 48 hours, the amount of free chlorine in the pool will be ____ppm.
Under certain water conditions, the free chlorine (hypochlorous acid, HOCl) in a swimming pool decomposes according to the law of uninhibited decay. After shocking a pool, the pool boy, Geoff, tested the water and found the amount of free chlorine to be 2.6 parts per million (ppm). Twenty-four hours later, Geoff tested the water again and found the amount of free chlorine to be 2.3 ppm. What will be the reading after 2days (that is,48 hours)? When the chlorine level reaches 1.0 ppm, Geoff must shock the pool again. How long can Geoff go before he must shock the pool again?
After 2 days or 48 hours, the amount of free chlorine in the pool will be ____ppm.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
