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MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS
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- SML programming Write a recursive function np(n) which takes a non negative n and generates a list of numbers from n+1 down to 0. You may assume that input of n is always valid. Must use identical function name and parameter(s). np(4)⟶[5,4,3,2,1,0]Consider the following recursive function: if b = 0, if 6 > a > 0, a f(b, a) f (b, 2.(a mod b)) otherwise. f(a, b) = Estimate the number of recursive applications required to compute f(a, b).Exercise 1: The number of combinations CR represents the number of subsets of cardi- nal p of a set of cardinal n. It is defined by C = 1 if p = 0 or if p = n, and by C = C+ C in the general case. An interesting property to nxC calculate the combinations is: C : Write the recursive function to solve this problem.
- The following function f uses recursion:def f(n):if n <= 1return nelsereturn f(n-1) + f(n-2)5Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n):a <- 0b <- 1if n = 0return aelsif n = 1return belsefor i in 1..nc <- a + ba <- bb <- creturn b b) def f(n):a <- 0i <- nwhile i > 0a <- a + i + (i-1)return a c) def f(n):arr[0] <- 0arr[1] <- 1if n <= 1return arr[n]elsefor i in 2..narr[i] <- arr[i-1] + arr[i-2]return arr[n] d) def f(n):arr[0..n] <- [0, ..., n]if n <= 1return arr[n]elsea <- 0for i in 0..na <- a + arr[i]return a*19. A recursive function f (x), is defined as follows: if (x>100) return (x-10) else return (f (f (x+11) ) ) For which of the following values of x, (a) 100 (b) 91 f(x) (c) 1 = 91? (d) 1018. Ackerman's Function Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performance of recursion. Design a function ackermann(m, n), which solves Ackermann's function. Use the following logic in your function: If m = 0 then return n + 1 If n = 0 then return ackermann(m-1,1) Otherwise, return ackermann(m-1,ackermann(m,n-1)) Once you've designed yyour function, test it by calling it with small values for m and n. Use Python.
- The following function f uses recursion:def f(n):if n <= 1return nelse return f(n-1) + f(n-2)Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion?a) def f(n):a <- 0b <- 1 if n = 0return aelsif n = 1 return belsefor i in 1..nc <- a + b a <- b b <- c return bb) def f(n):a <- 0i <- n while i > 0 a <- a + i + (i-1) return ac) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1return arr[n]elsefor i in 2..n arr[i] <- arr[i-1] + arr[i-2]return arr[n]d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1return arr[n]elsea <- 0 for i in 0..n a <- a + arr[i]return aFor function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}1. Below, enter code to complete implementation of a recursive function sum allintegers(), which takes an input n and adds all integers preceding it, up to n: add all integers(n):
- Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…complete the identified statement such that the recursive function funx(n+1) = n*funx(n-1), any positive integer value of n, and funx(1)=1. 1 float funx (int n) 3 if (n <= 1) 4 return l; else 6 return // complete this statement 7Write a recursive function definition for the following function: int squares(int n); //Precondition: n >= 1 //Returns the sum of the squares of numbers 1 through n. For example, squares(3) returns 14 because 12 + 22 + 32 is 14.