Two forces act on an object. The first force has a magnitude of 19.0 N and is oriented 68.0° counterclockwise from the +? axis, whereas the second force has x‑ and y‑components (−21.0 N,12.5 N).(−21.0 N,12.5 N). Express the magnitude and direction of the net force. direction: °counterclockwise from the +x‑axis

Two forces act on an object. The first force has a magnitude of 19.0 N and is oriented 68.0° counterclockwise from the +? axis, whereas the second force has x‑ and y‑components (−21.0 N,12.5 N).(−21.0 N,12.5 N). Express the magnitude and direction of the net force. direction: °counterclockwise from the +x‑axis

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 49P

See similar textbooks

Similar questions

Two forces act on an object. The first force has a magnitude of 17.0 N17.0 N and is oriented 68.0°68.0° counterclockwise from the +?+x‑axis, whereas the second force has ?x‑ and ?y‑components (−21.0 N,12.5 N).(−21.0 N,12.5 N). Express the magnitude and direction of the net force. magnitude: NN direction: °° counterclockwise from the +?+x‑axis
Problem 3: Find unit vector of a force. Find the unit vector corresponding to a 100 N force at 60° from the z-axis.
The force F has a magnitude of 520 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. B 15" F = 520 lb A j+ i k) M 8" Answers: Vector F = (520 lb)(i Scalar components Fx= i Fy=i F₂= i 11" lb lb lb i+ i
Three forces act on point P. Force A equals 80.0 N, 60.0°. Force B equals 70.0 N, 0.0°. Force C equals 40.0 N, 315.0°. (a) Add the vectors in the order A +B + C by the graphical method. (b) Draw and measure the sum of the same vectors but in a different order (e.g. C + A + B = ?) . (c) Are the answers to (a) and (b) the same? Should they be? Explain.
Two vectors are given by a = 1.5î−4.0ĵ and b = −11.9î + 8.1ĵ. What is the magnitude of b? i already found out magnitude of b is 1.44 but how to calculate the angle between vector b and the positive x-axis?
If a force is applied with a magnitude of 200 N at 30 degrees above the horizontal, what are the horizontal and vertical components of this force? Group of answer choices Fa,h= 136.667 N Fa,v= 87.334 N Fa,h= 200 N Fa,v= 200 N Fa,h= 173.2 N Fa,v= 100 N Fa,h= 150 n Fa,v= 50 N
A force is specified by the vector F = (190i + 80j - 100k) N. Calculate the angles made by F with the positive x-, y-, and z-axes. Answers: O ex= i i
A student's car stalls right in front of a speed bump while she is on her way to physics class. To pull it over the bump, she ties a cable to her bumper and to a nearby tree, and pulls with a force, F, of 81.0 lbs (360 N) at the midpoint in a perpendicular direction.If θ is 11.0°, what is the size of the force pulling the car in lbs
Two electric force vectors act on a particle. Their x-components are 14.5 N and −7.35 N and their y-components are −12.0 N and −4.70 N, respectively. For the resultant electric force, find the following. (a) the x-component (b) the y-component (c) the magnitude of the resultant electric force (d) the direction of the resultant electric force, measured counterclockwise from the positive x-axis
Determine the angles made by the vector V = -60i + 44j with the positive x- and y-axes. Write the unit vector n in the direction of V. Answers: 0x = ey= n= i+ i i i i
Starting from one oasis, a camel walks 25 km in a direction 30 ° south of west and then walks 30 km toward the north to a second oasis. What is the direction from the first oasis to the second oasis? A) 42 ° W of N B 51 ° W of N C) 69° N of W D) 21° N of W E 39° W of N
The magnitude of the force F is 720 Ib. Express F as a vector in terms of the unit vectors i and j. Identify both the scalar and vector components of F. Y, ft F = 720 Ib | -x, ft |_ 33° A (6,-1) Answers: Vector expression: F = (L 5) Ib the tolerance is +/-2% Scalar components: Fx = |Ib, Fy = Ib Vector components: Fx |i lb, Fy = Ib