Translate the following 'C' code to MIPS. NOTE: h is located in $s2, the base register of A is in $s3, and i is in $t0. for (i = 0; i = { A[7]; i++) h = h + i; } A[10] = h;
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- Lab8: (Bit Operations) Step1: Write a C program to learn bit operations. Step2: Write the following functions in C and test them: Multiply a number by 4 using shift Divide a number by 4 using shift - Bittest Bitcount - Bitor - Bitand BitxorBelow C-code has a for loop which will repeat 1000 times of the operation. This code will be running on very simple machine. Change the code to reduce the number of branch instructions. You can have up to 5 lines (statements) within the for loop. What is the number of branch operations before and after? for (i=0; i<1000; i++){ y[i] = w * x[i] + b[i]; }(Practice) State whether the following are valid function names and if so, whether they’re mnemonic names that convey some idea of the function’s purpose. If they are invalid names, state why. powerdensity m1234 newamp 1234 abcd total tangent absval computed b34a 34ab volts$ a2B3 while minVal sine $sine cosine speed netdistance sum return stack
- (b) Consider the following arithmetic expression in postfix notation: Postfix expression: a bc - + de f -g/h + * - i. Write the equivalent infix expression and prefix expression for the above expression. ii. Create an expression tree for the above expression.Write the following C code in RISCV without using any opcode and it should be able to run through the Cornell Computer Science interper. int x[100]; for(int i = 0; i < 10; i++) {x[i] = *i; }Identify the postfix version of this infix expression: (a + b) * (c / d) a b c d + * / a b + c d / * a b + * c d / c d / a b + *
- 4. Convert the following Boolean expression to the sum of minterms form. f(a, b, c) = a'b' + bc + ac' 5. Convert the following Boolean expression to the product of maxterms form. f(a, b, c) = a + bcUsing the following description, please replace the return line in C code; /* * addOK: determine if x+y succeeds without overflow * Examples: * addOK(0x40000000,0x20000000) = 1 * addOK(0x40000000,0x40000000) = 0 * addOK(0x55555555,0x2AAAAAAA) = 1 * addOK(0x55555555,0x2AAAAAAB) = 0 * addOK(0x80000000,0x40000000) = 1 * addOK(0x80000000,0x80000000) = 0 * Legal ops: ! ~ & ^ | + << >> * Max ops: 20 * */ int addOK(int x, int y) { return 2 } You cannot: 1. Use any control constructs such as if, do, while, for, switch, etc. 2. Define or use any macros. 3. Define any additional functions in this file. 4. Call any functions. 5. Use any other operations, such as &&, ||, -, or ?:, not listed in the the "Legal ops" list for the function. 6. Use any form of casting. 7. Use any data type other than int.Do not use array or advance logic simple c++ Write and test the “digit” function:Function Prototype: int digit(int n,int k)This function returns the kth digit of the positive integer n. For example, if n is the integer29,415, then the call digit(n,0) would return the digit 2, and the call digit(n,2) would returnthe digit 4.Examples:Input: n = 29415 , k = 1 output: 9Marks: 02Input: n = 2 , k = 0 output: 2 n = 2 , k = 1 output: index out of bound (return -1)Note:• The digits are numbered from left to right beginning with the “zeroth” digit.• Take input and display output in main function.
- Coding Assignment 1.Suppose, the value of three registers X, Y, Z are given along with the number of key bits. You need to generate the key accordingly. (Use Java or Python) **Print important variables inside your code for debugging purpose. Make necessary assumption where needed.Change the following infix expression to a postfix expression A*B+C*D (A+B)*(C–D) ((A+B)*C)–D A+B*(C–D/(E+F))translate the following MIPS code to C. Assume that the variables i, j, and k areassigned to the registers $s0, $s1, and $s2, respectively. Assume that the baseaddress of the array A is in registers $s6.Loop: blt $s0, $s1, Exitbge $s1, $s2, Exitaddi $s1, $s1, 5j LoopExit:addi $t0, $zero, 4ble $s0, $t0, Donesll $t1, $s0, 2add $t2, $s6, $t1sw $zero, 0($t2)Done: