Transfer elements from stack S1 to stack S2 so that the elements from S2 are in the same order as on S1 using one additional stack using no additional stack but only some additional non-array variables
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- Transfer elements from stack S1 to stack S2 so that the elements from S2 are in the same order as on S1
- using one additional stack
- using no additional stack but only some additional non-array variables
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- Consider the Stack ADT: Stack: push(x) adds x to top of stack pop() removes top element of stack and returns it size() returns number of elements in stack Select all options that allow for an efficient implementation based on the discussions from class. For any array implementation, you can assume the array is large enough so that making a larger one is not needed when pushing an item to the stack. Using an array with the top at the front of the array. Using an array with the top at the back of the array. Using a singly linked list with the top at the head of the list. Using a singly linked list with the top at the tail of the list. ENGExamine the performance of the stack under situations in which it is allowed to act naturally.Determine how the stack behaves when it is permitted to operate on its own.
- A drop-out stack is a data structure that acts just like a stack except that if the stack size is n, and the n + 1 element is pushed, the first element is lost. Using an array, create a drop-out stack. (Hint: A circular array implementation would be appropriate.)Determine the stack's performance when free.You may operate on a stack WORK and a temporary stack TEMP (if necessary) to enable its ADT operations of PUSH (S,X), POP (S, X), and EMPTYSTACK (S), where X represents an element/variable to be pushed into or popped out of the stack and S represents a stack. You may also utilise one variable to carry out the procedures if necessary. I Given n different random integers to be pushed into WORK, how can you determine the maximum element pushed into it while ensuring that the items placed in WORK are in decreasing order, with the maximum element beginning at the bottom of the stack? You may utilise a single variable and the temporary stack TEMP. ii) Given an array A[1: n] of different random numbers, how can you extract the array's sorted list using only stacks?
- A data structure known as a drop-out stack functions exactly like a stack, with the exception that if the stack size is n, the first element is lost when the n + 1 element is pushed. Apply an array to a drop-out stack. (Hint: It would make sense to implement a circular array.)A data structure known as a drop-out stack functions exactly like a stack, with the exception that if the stack size is n, the first element is lost when the n + 1 element is pushed. Use an array to implement a drop-out stack. (Hint: It would make sense to implement a circular array.)Stack: push(x) adds x to top of stack pop() removes top element of stack and returns it size() returns number of elements in stack Select all options that allow for an efficient implementation based on the discussions from class. For any array implementation, you can assume the array is large enough so that making a larger one is not needed when pushing an item to the stack. Using an array with the top at the front of the array. Using an array with the top at the back of the array. Using a singly linked list with the top at the head of the list. Using a singly linked list with the top at the tail of the list. None of these choices allows for an efficient implementation of all methods.
- Observe the stack's reaction when given some space.Develop an application using java language that store characters A, B and C in a stack array and then displays both the size and the last-in element of the stack. The application should then remove the last element of the stack and then display again both the size and the last-in element of the stack. Appropriate stack methods should be used to add, delete and display characters.Select the statements that apply to the use of the frame pointer. EBP is often called the base pointer or frame pointer because it holds the base address of the stack frame. EBP does not changes value during the procedure. EBP need not be restored to its original value when a procedure returns. A procedure can explicitly access stack parameters using constant offsets from EBP.