Trait R is a Mendelian trait in humans for tongue rolling. The allele for the ability to roll the tongue (R) is dominant over the allele for the inability to roll the tongue (r). If both a mother and father are heterozygotes with respect to this trait, what is the likelihood that their offspring will also be a heterozygote for that trait? O 100% O 25% O 75% O 0% O 50%
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- As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyIn humans, the allele for a long second toe (L) is dominant. The allele for short second toe (I) is recessive. A woman who is homozygous for the long toe trait marries a man who has a short second toe. What is the probability that this couple's child will have short second toes? Use a pencil and piece of paper to draw the Punnett square for this cross to help you determine the correct answer. 100% O 0% O 50% O 25% 4 Previous NextThere are two types of alleles: Type B1 and Type B2 (In total there are 10) Type B1 has 6 Type B2 has 4 Question: What is the probability of an individual in the offspring generation being homozygous [p^2] for B1? What is the probability of an individual in the offspring generation being homozygous [q^2] for B2? What is the probability of an individual in the offspring gen being heterozygous[2pq]?
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- A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couple's children should have no widow's peak and no hitchhiker's thumb? 1/4 1/8 1/2 3/8 3/4 A2)Using the forked line method, determine the phenotypic ratio of a trihybrid cross between AaBbCc X AaBBCC. What proportion of offspring will have the dominant phenotype for A, B, and C? 1/8 1/4 1/16 3/4 1/2 A3) How many different offspring genotypes are expected in a trihybrid cross between parents heterozygous for all three traits when the traits behave in a dominant and recessive pattern? How many phenotypes? 8 genotypes; 27 phenotypes 27 genotypes; 8 phenotypes 16 genotypes; 64 phenotypes 64 genotypes; 16 phenotypesUsing the concepts of non-mendelian genetics, what is the phenotypic ratio of the offspring if two heterozygous pea plants with purple flowers are crossed together? O 3 pea plants with light purple flowers: 1 pea plant with a single mixed color for white and purple color. O 3 pea plants with purple flowers: 1 pea plant with light violet flowers. O 1 pea plant with purple flowers: 2 pea plants with white flowers: 1 pea plant with mixed color for white and purple color. O 1 pea plant with purple flowers: 2 pea plants with light purple flowers: 1: pea plant with white flowers.The ability to taste PTC paper is controlled by a dominant allele. The ability to taste (T) is dominant over the inablity to taste (t). Normal skin (N) is dominant over albino skin (n). Two tasters, normally pigmented, have an albino son and a non-taster daughter. Show the cross between the parents. What is the chance that the albino son is a taster? What is the chance that the non-taster daughter is an albino? What is the chance that the non-taster daughter is a carrier of the albino trait? What is the chance of getting offspring who are heterozygous for both traits?
- In humans the absence of a cleft chin is dominant to the presence of a cleft chin. Two individuals, both of whom are heterozygous for a recessive allele that causes the cleft chin phenotype have 5 children, what is the probability that 3 of their children would not have a cleft chin and 2 would have a cleft chin? 0.0037 0.026 0.237 0.264In man, there is gradation in eye color and resulting to 9 phenotypes. These are (in order of the number of additive alleles): light blue, medium blue, dark blue, gray, green, hazel, light brown, medium brown, dark brown. Mr. A (dark brown eyes) and Mrs. A’s (light blue eyes) daughter, marries a man whose genotype is the same as herself. What is the probability that they could have: Dark brown eyed child? Hazel-eyed? What eye color is most likely to occur and what is its probability?Mendel's law of segregation states that only one of the two gene copies present in an organism is distributed to each gamete (egg or sperm cell) that it makes, and that the distribution of the alleles is random. According to Mendel's law of segregation, which of the following letters is missing in the Punnett square at location X if a pea plant with the genotype Rr is crossed with a pea plant Rr R. ORr RR
