Give the structure of the compound and explainexactly how you reached this conclusion.TolueneINFRARED SPECTRUM0.80.60.40.2300020001000Wavenumber (cm-1)NIST Chemistry WebBook (https://webbook.nist.gov/chemistry)7.38 to 7.002.34HzppmInt.656.75651.38650.80649.81648.637.3347.2747.2687.2567.2437.2202938295010899646.56645.69644.25643.31641.81641.13640.50639.697.2107.1947.184948297077.1677.1597.1527.14324614112285638.94638.06637.25636.25635.75209.757.1357.1257.1167.1057.0992.34365625055106.5.55841000PpmTRANSMITTANCE

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Toluene INFRARED SPECTRUM 0.8 0.6 0.4 0.2 3000 2000 Wavenumber (cm-1) 1000 NIST Chemistry WebBook (https://webbook.nist.gov/chemistry) 7.38 to 7.00 2.34 Ppm Int. 656.75 651.38 650.88 649.81 648.63 7.334 7.274 7.268 7.256 7.243 7.220 7.210 7.194 29 38 29 50 108 99 646.56 645.69 644.25 643.31 641.81 94 829 707 246 641.13 640.50 639.69 638.94 638.06 637.25 636.25 7.184 7.167 7.159 7.152 7.143 7.135 7.125 141 122 85 65 62 50 55 7.116 7.105 7.099 2.343 10 2 635.75 55 209.75 1000 ppm TRANSMITTANCE

Toluene INFRARED SPECTRUM 0.8 0.6 0.4 0.2 3000 2000 Wavenumber (cm-1) 1000 NIST Chemistry WebBook (https://webbook.nist.gov/chemistry) 7.38 to 7.00 2.34 Ppm Int. 656.75 651.38 650.88 649.81 648.63 7.334 7.274 7.268 7.256 7.243 7.220 7.210 7.194 29 38 29 50 108 99 646.56 645.69 644.25 643.31 641.81 94 829 707 246 641.13 640.50 639.69 638.94 638.06 637.25 636.25 7.184 7.167 7.159 7.152 7.143 7.135 7.125 141 122 85 65 62 50 55 7.116 7.105 7.099 2.343 10 2 635.75 55 209.75 1000 ppm TRANSMITTANCE

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL3: Carbon (13c) Nmr Spectroscopy

Section: Chapter Questions

Problem 9CTQ

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7) The correct structure that corresponds to the spectroscopic data given below is [IR 2720, 1710 1 point cm*1. 1H NMR 9.80(s, 1H), 7.50(dd, J = 8,0Hz, 2Hz, 1H), 7.40(d, J = 2.0Hz, 1H), 6.90(d, J = 8.0Hz, 1H), 3.90(s, 3H), 3.80(s, 3H)] COOH OMe Me CHO OMe OMe CHO OMe OMe COOH OMe Me
/351142db-11b4-465e-8145-7af70e490f5f/jsf/delivery/deliverAsSsessment Soru 4/8 15 Puan Analyse the high resolution proton NMR spectrum and suggest a compound and write its name. Aslo write down which parts of the molecule belongs to each peak. wg er 's 00 H Spectum C,H1002 Expanded peak duster at 2 32 ppm Expanded peak ster at413 pom Expanded peak clusters at 1 26 and 114 ppm (Maksimum karakter sayısı: 60000) << Zengin-Metin Editorunu (ye karakter hesaplamal Goster Tumüno goster 101 A Organicstructuresf..pdf TR 11.02 2021
645. Give the structure of the compound and explain exactly how you reached this conclusion. Toluene INFRARED SPECTRUM 0.8 OR 0.6 0.4 3000 2000 1000 Wavenumber (cm-1) NIST Chemistry Webeook (https://webbook.nist.gov/chemistry) 7.38 to 7.00 2.34 P Int. E56.75 1.334 651.38 7.274 650.88 7.268 649.81 7.256 648.63 7.243 7.220 7.210 644.25 7.194 643.31 7.184 641.81 7.167 7.159 640.50 7.152 639.69 .143 7.135 638.06 7.125 29 38 29 50 108 646.56 645.69 94 829 707 246 641.13 141 122 es 638.94 62 637.25 7.116 50 636.25 7.105 635.75 7.099 209.75 2.343 55 10 55 1000 Ppm Which compound is this? HydrocarbonsDiphenylmethane "1,1-Diphenylethene "Toluene "Isopropylbenzene "Styrene Halides2-Bromopropane "1-Chloro-1-phenylethane "1-Chloro-2-phenylethane "1,3-Dichloropropane "1,4-Dichlorobutane "1-Bromopropane "p-Bromoethylbenzene "lodoethane "2-Bromobutane "Chlorodiphenylmethane Alcohols2-Propanol "2-Phenylethanol "1-Phenylethanol "Ethanol EthersEthoxybenzene "Diisopropyl ether "Benzyl ethyl ether…
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NMR data Summary NMR solvent: DMSO-d6 'H NMR: Splitting (Multiplicity) Integration Chemical Shift 9.67 singlet 1H singlet doublet 9.17 7.37 6.72 2.00 1H 2H doublet singlet 2H 3H 1"C NMR: Chemical Shift 167.8 153.3 131.1 121.1 115.1 23.8 15N NMR: Chemical Shift 132.3 Instructions: Step 0: Look at the structure of Tylenol. Determine integration, and splitting you are expecting in the 'H NMR. Step 1: Look at the integration and splitting of the signals in the H NMR spectrum - assign the chemical shift of the protons of the methyl group; make a note which signals in the 'H NMR are due aromatic protons, NH and/or OH. Step 2: Look at the 'HSN HSQC spectrum - Use this spectrum to assign the chemical shifts of the NH proton and the OH proton. Step 3: Look at the 'H1SN HMBC spectrum - Use this spectrum to assign the chemical shifts of the aromatic protons in the 'H NMR. Step 4: Look at the 13C NMR spectrum - Make a note which carbon atoms are aromatic and/or alkyl. Assign the chemical shift of…
A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-lijkPWvZOZLqKt1FLIq7wcPWKzBYGFE9IMFj-vdLgkbljMnFEN-B2dRSRM8FDfp-D Knowledge Check Question 20 Calculate the volume of liquid in the NMR tube sketched below. Give your answer in microliters, and round to the nearest 1 uL. 1.71 cm L ? 2.7 mm I Don't Know Submit © 2021 McGraw-Hill Education. All Riahts Reserved. Ter II
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13C NMR Analysis of Aspirin Chemical Shift (Observed ppm) Assignment(s) (A'-J') Expected Chemical Shift Range (ppm) B' D' E' JOH Acetylsalicylic Acid (Aspirin) 169 & 170 152 125 135 (4 peaks) - 122 20 160 140 120 100 Figure 14.13 125.7-MHz 13C-NMR spectrum of aspirin in CDCl3. solvent 80 60 40 20 ppm
Molecular Formula: C10H14 8 LOD TRANSMITTANCE1% D 4000 STRUCTURE: mult. t 2.72 q 6.90 S d t ppm 1.18 7.11 7.53 3000 H 6 4 1 2 1 5 2000 SPECTRUM 5 4 PPM HAVENUMBERI-L 1500 3 1000 500
Spectroscopic Analysis https://www.youtube.com/watch?v=ZfMPyZiDsf4&list=PLE-217H0ao60Uzpzj-FNP_0ScVp5SZB7j&index=2 watch the following question and read the article to answer the questions Spectroscopic Analysis-1 a.Which of the following statements regarding IR spectroscopy is wrong? Infrared radiation is higher in energy than UV radiation. Infrared spectra record the transmission of IR radiation. Molecular vibrations are due to periodic motions of atoms in molecules, and include bond stretching, torsional changes, and bond angle changes. Infrared spectra give information about bonding features and functional groups in molecules. b.Which is the correct order of decreasing wave number of the stretching vibrations of (1) C-H (alkane), (2) C-H (alkene), (3) C-H (alkyne), and (4) C=O? (1) > (2) >(3) >(4) (4) < (3) < (2) < (1) (3) < (4) ≈ (2) < (1) (1) < (4)…